a.3/4 b.7/64 c.3/16 d.15/28
2006-08-15 07:44:37 · 14 answers · asked by guitarkhongday 1 in Science & Mathematics ➔ Mathematics
7 / 64 (B)
2006-08-19 02:26:49 · answer #1 · answered by Joe Mkt 3 · 2⤊ 0⤋
Depends -- do you mean exactly 6 times, or at least 6 times?
Assuming you mean exactly 6 times, we can easily answer the equivalent question: what's the probability that exactly two of the throws come up heads?
Number the throws 1-8, and consider the possibilities:
* the first of the two heads could be Toss #1; the other head is then one of the other 7. (That's 7 possibilities.)
* the first of the two heads could be Toss #2; the other head is then one of the other 6.
* the first of the two heads could be Toss #3; the other head is then one of the other 5.
In the end, we have 7+6+5+4+3+2+1 = 28 different possibilities for 2 heads. Since there are 2^8 = 256 total ways to toss a coin 8 times, our probability of 2 heads is therefore 28/256, or 7/64.
Hope that helps!
2006-08-15 07:48:19 · answer #2 · answered by Jay H 5 · 0⤊ 0⤋
You didn't specify, but I'm going to assume you mean exactly 6 tails (not less and not more).
Asking for the probability of having exactly 6 tails is the same as asking for the probability with exactly 2 heads. In my head, that's a slightly easier problem to solve.
The total number of different outcomes is:
2^8 = 256
The number of possible outcomes that have exactly 2 heads:
7 + 6 + 5 + 4 + 3 + 2 + 1 = 28
Probability the throw will have exactly 2 heads (and exactly 6 tails):
28 / 256 = 7 / 64
The correct answer is B.
2006-08-15 08:05:07 · answer #3 · answered by Iowan4321 2 · 0⤊ 0⤋
There are 28 ways (8Choose6) to get 6 tails in 8 tosses. The total number of ways that 8 tosses can come out is 2^8 so the probability of getting 6 tails in 8 tosses is
28/256 which is 7/64.
Doug
2006-08-15 07:58:14 · answer #4 · answered by doug_donaghue 7 · 0⤊ 0⤋
3/4
2006-08-15 07:49:41 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Cannot tell without the results of the other 2 tosses, but the total number of possible outcomes without ordering is 2^6 or 64.
2006-08-15 07:51:09 · answer #6 · answered by Answers1 6 · 0⤊ 0⤋
How many ways can it happen: 8 Choose 6.
How many different ways can you toss 2^8
The answer is 28/256 or 7/64
2006-08-15 07:56:36 · answer #7 · answered by tbolling2 4 · 0⤊ 0⤋
it is (a) 3/4
2006-08-15 07:54:37 · answer #8 · answered by raj 7 · 0⤊ 0⤋
B, because it is 1/2 for 4 times with tails. So if you maximize the frequency of having tails, you thus minimize the probability of it actually happening.
2006-08-15 10:18:06 · answer #9 · answered by Anonymous · 0⤊ 0⤋
the order doesnt matter, and the prob for tails is 50%
6/8
= 3/4
=a
2006-08-15 07:55:14 · answer #10 · answered by jasonalwaysready 4 · 0⤊ 0⤋
Assuming you mean exactly 6 times...b.7/64.
2006-08-15 07:58:45 · answer #11 · answered by Anonymous · 0⤊ 0⤋