3*5^2+5*5-7 = 93 which will be the remainder you'll get if you do the synthetic division.
Doug
2006-08-15 06:51:04
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answer #1
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answered by doug_donaghue 7
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Let f(t) = 3t^2 + 5t -7 ......................i
Since we have to divide by (t-5)
Therefore put t -5 =0
or t=5
Put t=5 in i
f(5) = 3(5)^2 + 5(5) -7
= 75 +25 -7
= 93
Hence the remainder is 93
2006-08-15 07:23:12
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answer #2
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answered by Amar Soni 7
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Plug t=5 into your polynomial. The remainder theorem says that this will be the remainder if you had divided.
2006-08-15 06:46:28
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answer #3
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answered by mathematician 7
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The remainder is: 93/(t-5) not 93!
2006-08-15 08:54:37
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answer #4
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answered by Anonymous
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2x + 5 = 0 x = - 5 / 2 8x^3 - 24x + sixty 5 =8x^3 +0x^2 -24x + sixty 5 the rest theorem: 8 0 -24 sixty 5 |_-5/2 -20 -50 -sixty 5 + + + --------------------------------------... 8 + 20 +26 +a hundred thirty consequently, the rest = a hundred thirty
2016-12-11 09:11:51
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answer #5
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answered by ? 4
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see http://library.thinkquest.org/C0110248/algebra/remfactintro.htm
for a very good breakdown.
2006-08-15 06:51:37
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answer #6
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answered by starr_man 1
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