2006-08-15 06:08:39 · 25 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
16
2006-08-19 02:18:12 · answer #1 · answered by Joe Mkt 3 · 2⤊ 0⤋
the answer is 17. word that 17 + 18 + 19 = fifty 4. You solved it by technique of letting n be the smallest integer. Then make an equation by technique of letting the subsequent 2 consecutive integers be n + a million and n + 2. Then n + (n + a million) + (n + 2) = fifty 4 3*n + 3 = fifty 4 sparkling up for n.
2016-11-25 19:23:38 · answer #2 · answered by ? 4 · 0⤊ 0⤋
An even integer is represented as 2X, next even integer is 2 places after 2X so it is 2X + 2 and third integer is 2X+4.
2X + 2X+2 + 2x +4 = 54
= 6X + 6 = 54
= 6X = 54-6 = 48
= X = 48/6 = 8.
So 2X = 16
The 3 numbers are 16, 18 and 20.
Your question should be what is the first integer? Then it is 16.
as per your question, the first consecutive integer is 16 + 2 = 18.
I donno what you meant.
2006-08-19 01:58:44 · answer #3 · answered by StraightDrive 6 · 0⤊ 0⤋
16
2006-08-15 06:14:19 · answer #4 · answered by Anonymous · 1⤊ 0⤋
16
2006-08-15 06:13:52 · answer #5 · answered by jurydoc 7 · 1⤊ 0⤋
16 is definitely right, the question says "3 consecutive EVEN integers", so x + (x+2) + (x+4)
2006-08-15 06:26:46 · answer #6 · answered by Jaq 2 · 1⤊ 0⤋
17
2006-08-15 06:16:30 · answer #7 · answered by bobpegoh 2 · 0⤊ 1⤋
17
2006-08-15 06:13:49 · answer #8 · answered by J.D. 6 · 0⤊ 1⤋
17
2006-08-15 06:13:46 · answer #9 · answered by raj 7 · 0⤊ 1⤋
The answer is definitively ... 16
16 + 18 +20=54
2006-08-15 06:15:37 · answer #10 · answered by Anonymous · 1⤊ 0⤋