2006-08-15 05:39:33 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
51
2006-08-19 02:12:55 · answer #1 · answered by Joe Mkt 3 · 2⤊ 0⤋
50+51+52=153
2006-08-15 12:48:17 · answer #2 · answered by sparkles_0604 3 · 0⤊ 0⤋
Divide 153 by 3 = 51.
2006-08-15 12:44:46 · answer #3 · answered by silverwhiskers 2 · 2⤊ 0⤋
Let three consecutivee numbers are n-1,n , n+1
since their sum is 153, therefore
(n-1) + (n) + (n+1) = 153
n-1 +n +n+1=153
3n= 153
Therefore n=51
Hence the middle number is 51 or seond number is 51
2006-08-15 12:55:28 · answer #4 · answered by Amar Soni 7 · 1⤊ 0⤋
51
50+51+52 = 153
2006-08-15 12:43:37 · answer #5 · answered by Krzysztof_98 2 · 1⤊ 0⤋
153/3=51
2006-08-15 12:56:51 · answer #6 · answered by raj 7 · 0⤊ 0⤋
dotz u let de smallest integer be x and so de 2nd smallest is x+1 and largest is x+2.. add all 3 u get 3x + 3 = 153, therefore 2nd integer is x + 1 = 51 =)
2006-08-15 12:48:17 · answer #7 · answered by ThoughTs 2 · 1⤊ 0⤋
let x=2nd #
so 1st # = x-1
3rd # = x+1
the sum is 153:
(x - 1) + x + (x + 1) = 153
x - 1 + x + x + 1 = 153
Rearranging:
x+x+x+1-1 = 153
3x = 153
x= 153/3 = 51
2006-08-15 12:49:40 · answer #8 · answered by dennis_d_wurm 4 · 1⤊ 0⤋
It's 50+51+52 = 153
So 51
Doug
2006-08-15 12:45:42 · answer #9 · answered by doug_donaghue 7 · 1⤊ 0⤋
x + (x + 1) + (x + 2) = 153
x + x + 1 + x + 2 = 153
3x + 3 = 153
3x = 150
x = 50
The numbers are 50, 51, and 52
ANS : 51
2006-08-15 17:09:19 · answer #10 · answered by Sherman81 6 · 0⤊ 0⤋