math question?

0 ⤊

Find dy/dx by logarithmic differentiation

y=(1+x^2)^3/2 / (1+x^3)^4/3

2006-08-15 05:32:15 · 3 answers · asked by tim w 1 in Education & Reference ➔ Homework Help

logy
=3/2 log(1+x^2)-4/3log(1+x^3)
=1/y*dy/dx=2x/(1+x^2)-16x^2/(1+x^3)
dy/dx=[(1=x^2)^3/2/(1+x^3)^4/3]
[2x/(1+x^2)-16x^2/(1=X^3)]

2006-08-15 05:47:00 · answer #1 · answered by raj 7 · 0⤊ 0⤋

167

2006-08-15 05:37:24 · answer #2 · answered by farts0 1 · 0⤊ 0⤋

ok i sugest you borrow (or buy) a graphing calculator then when you know the ancer play games on it

2006-08-15 05:38:42 · answer #3 · answered by ineedacar 5 · 0⤊ 0⤋