Pls. help me solve this math problem. Please include the GCF (greatest common factor) in your answer. Thankyou!!!
2006-08-15 04:32:08 · 8 answers · asked by Andrea 1 in Science & Mathematics ➔ Mathematics
475 = 5 * 5 * 19
399 = 3 * 7 * 19
190 = 2 * 5 * 19
GCF = 19
2006-08-19 01:55:35 · answer #1 · answered by Joe Mkt 3 · 2⤊ 0⤋
475=5*5*19
399=3*7*19
190=2*5*19
so the GCF is 19 as no othetr factor is common
2006-08-15 05:06:27 · answer #2 · answered by raj 7 · 0⤊ 0⤋
19
Make prime decomposition:
190 = 2 * 5 * 19
399 = 3 * 7 * 19
475 = 5 * 5 * 19
The factors all three have in common are only the 19s.
2006-08-15 04:38:04 · answer #3 · answered by dutch_prof 4 · 0⤊ 0⤋
475 | 5
95 | 5
19 | 19
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
399 | 3 because 399 divided by 3 equals 95
95 | 7 because 95 divided by 7 equals 19
19 | 19 because 19 divided by 19 equals 1
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
190| 2 because 190 divided by 2 equals 95
95 | 5 because 95 divided by 5 equals 19
19 | 19 because 19 divided by 19 equals
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
The common factor
497 , 399 and 190 is 19
The answer is 19
2006-08-15 04:59:20 · answer #4 · answered by SAMUEL D 7 · 0⤊ 0⤋
go by decomposition the prime nuber is 19 with quatants 0f 10 21 and 25
2006-08-15 04:45:16 · answer #5 · answered by walkietalkie899 1 · 0⤊ 0⤋
19 is the only common factor.
2006-08-15 04:40:34 · answer #6 · answered by knivetsil 2 · 0⤊ 0⤋
all are divisible by 19(10, 21, 25 are the quotients)
2006-08-15 04:39:15 · answer #7 · answered by ponyboy 81 5 · 0⤊ 0⤋
Use Euclids division algorithm. Se:
http://people.uncw.edu/norris/133_fa04/proofs/quotientRemainderTheorem.htm
or go to
http://people.uncw.edu/tompkinsj/133/Numbers/EuclidsDivisionAlgorithm.html
for a very kewl Java applet that does it for you.
Doug
2006-08-15 05:31:09 · answer #8 · answered by doug_donaghue 7 · 0⤊ 0⤋