AB x C= AAA
2006-08-15 04:28:41 · 6 answers · asked by chaneld2005 1 in Science & Mathematics ➔ Mathematics
37 x 9 = 333
He means find 3 such positive integers such that AB x C = AAA
111 doesnt work as its factors are only 3 and 37, So try 333 and it works, 555, 777 and 999 are all multiples of 37, so they cannot factorise to a 2-digit and a 1-digit pair of factors (555 = 15 x 37 or 111 x 5) hence the solution above is the only solution.
2006-08-15 04:37:53 · answer #1 · answered by Anonymous · 4⤊ 0⤋
obviously, AAA is a multiple of 111.
111 = 3 * 37, so we must have AB = 37 and C a multiple of 3.
But then A = 3, B = 7, and C = 9
37 * 9 = 333
2006-08-15 04:39:34 · answer #2 · answered by dutch_prof 4 · 0⤊ 0⤋
By mathematical experience,
AB * C = AAA
37 * 9 = 333
A = 3 B = 7 C = 9
2006-08-19 01:58:22 · answer #3 · answered by Joe Mkt 3 · 0⤊ 0⤋
A=3
B=7
C=9
37 x 9 =333
2006-08-15 04:38:18 · answer #4 · answered by knivetsil 2 · 0⤊ 0⤋
AB x C = AC + BC
2006-08-15 04:33:59 · answer #5 · answered by wing_gundam 3 · 0⤊ 0⤋
....eerrr....your question does not make any sense to me..
2006-08-15 04:36:07 · answer #6 · answered by AriS 2 · 0⤊ 0⤋