logarithm of one plus square root of x is equal to logarithm of x to the base three .find x.
2006-08-15 03:59:33 · 4 answers · asked by student 1 in Education & Reference ➔ Primary & Secondary Education
I tried to do it, but the answer is not right when I put it back into the equation. Maybe you can see what is wrong. Here are my steps:
log(1+ square root of x) = log 3 (x)
log(1+ square root of x) = log(x)/log(3)
10 ^ (log(x)/log(3)) = 1+ square root of x
x/3 = 1+ square root of x
x = 3 + 3*square root of x
x-3 = 3*square root of x
(x-3)^2 = (3*square root of x)^2
x^2 -6x+9 = 9x
x^2 -15x+9 = 0
x = 0.6261364576 or 14.37386354
however, the first one is wrong because it's the answer that got added on because of my changing the degree of the original equation. The second one is closer to the correct answer.
Sorry that I couldn't be completely helpful. I hope you get the answer!
2006-08-15 05:11:51 · answer #1 · answered by flit 4 · 0⤊ 0⤋
It is very tough question. But it is solved book.
2006-08-15 04:41:45 · answer #2 · answered by RAMAN IOBIAN 7 · 0⤊ 0⤋
do u mean algorithms?
2006-08-15 05:26:49 · answer #3 · answered by Amanda E 1 · 0⤊ 0⤋
keep me away from maths..............though am an engineerin' student.......!.......chill solve it urself
2006-08-15 04:36:42 · answer #4 · answered by jass 3 · 0⤊ 0⤋