can u answer these?

Question

if u can find the answers 4 these, please tell me how u did it.

State wheter the given lenghts can form a triangle:
1. 8 in, 4in, and 11 in.
2. 30 cm, 20 cm, 10cm.
3. 8m, 8m, 18m.

Answer 1

yes for number 1 only

add lengths of the two shorter sides, if the sum equals or does not exceed
the longest side, no triangle is formed

subtract lengths of the two longer sides, if the difference equals or exceeds the shortest side, no triangle is formed

!_! ;-)...

Answer 2

In order for the lengths to work as a triangle, there's a property of triangles that has to be recognized: the sum of any two sides is greater than (not less than *or* equal to) the third side.

In the first case, for instance:
8 + 4 > 11,
8 + 11 > 4, and
4 + 11 > 8

Since each possible pair of sides adds up to more than the leftover side, these three segments can be the sides of a triangle.

Try that same test on the other two, and see if they all work. Good luck!

Answer 3

1. 8 in, 4in, and 11 in.
yes
2. 30 cm, 20 cm, 10cm.
no
3. 8m, 8m, 18m.
no
the rule is two sides together should be greater than the third side

Answer 4

Assumption

The Lengths of a triangle

The opposite side

The adjacent side

and the Hypotenuse

In a triangle the lengths of the Opposite side Plus the lenght of the adjacent side, there sum exceeds the total lenght of the Hypotenuse.

-- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

1). 8in + 4in = 12 in

This meets the qualifications

2). 30cm + 20cm = 50cm

This does not qualify

3). 8m + 8m = 16m

This does not qualify

Answer 5

Only Number one. Are you going to do any of your homework yourself?

Answer 6

use a ruler, test it out

Answer 7

they can.. and if they cant form another shape