A 20drops of dilute hydrochloric acid
10mL of solution containing 0.1 g caustic soda
B ?drops of dilute hydrochloric acid
10mL of solution containing 0.01 g caustic soda
Please explain
2006-08-15 01:30:50 · 9 answers · asked by Grant 1 in Science & Mathematics ➔ Chemistry
2 drops. The density of the caustic soda in solution B is one-tenth of that in solution A, so one-tenth as much hcl is required.
2006-08-15 01:33:11 · answer #1 · answered by Anonymous · 2⤊ 0⤋
2 drops.
Solution B has one tenth the amount as solution A, so it should only need one tenth of hydrochloric to dilute it.
One tenth of 20 drops = 2 drops.
2006-08-15 08:35:24 · answer #2 · answered by Pronkville 3 · 0⤊ 0⤋
N1V1=N2V2
so if the strength becomes 1/10th the volume for neutralizing will also be 1/10th and 1/10th of 20 ml or 20 drops is2 drops
2006-08-15 08:49:47 · answer #3 · answered by raj 7 · 0⤊ 0⤋
2. Solution B has one thenth as much soda as solution A in the same amount of liquid. To get how much HCl will be needed just divide the amount needed for A by ten.
2006-08-15 08:35:14 · answer #4 · answered by vampire_kitti 6 · 0⤊ 0⤋
2 drops
2006-08-15 08:54:12 · answer #5 · answered by C K Platypus 6 · 0⤊ 0⤋
you would need 2 drops.
first use to formula D= M/V
so for A it would be .1g/.o1L=10
B would be .01g/.01L=1
so now you have the densities so you can set up a proportion to find the drops.
so 20drops/10x ?/1=2
And thats how 2 is the answer
2006-08-15 11:13:02 · answer #6 · answered by antonette_lawrence 2 · 0⤊ 0⤋
I'd have guessed 2 as well. It appears to be simple maths. However quoting me might not be a good idea. So, no best answer here!
2006-08-15 08:36:28 · answer #7 · answered by Die Cocksucker 3 · 0⤊ 0⤋
200 drops
2006-08-15 08:33:36 · answer #8 · answered by Kevin N 3 · 0⤊ 4⤋
Why are you trying to get us to do your homework for us?
2006-08-15 08:33:00 · answer #9 · answered by Elana 7 · 1⤊ 0⤋