Simple Maths?

Question

.

10 ( 4 + 1) x (..... 4......)........... {Thats 4 over S then + 1}
....... S...............S + 12.................{Thats 4 over S + 12} Ignore the dots - just for spacing

Somehow = this below don't know how

40( 4 + S ) { Thats 40 ( 4 + S) all over S (S + 12) }
S ( S + 12)

Thank you.

Answer 1

10(4 / s + 1) · 4 / (s + 12) {Distribute the 10.}
= (40 / s + 10) · [4 / (s + 12)] {Distribute the [4 / (s + 12)].}
= 160 / [s(s + 12)] + 40 / (s + 12) {Get common denominator.}
= 160 / [s(s + 12)] + 40s / [s(s + 12)] {Factor out 40 / [s(s + 12)].}
= 40(4 + s) / [s(s + 12)]

Answer 2

Okay, I assume you mean 10(4/S + 1) * 4/(S+12), right? Then:

10(4/S + 1) * 4/(S+12)

Change 1 to S/S (we can do this because anything divided by itself is 1):

10(4/S + S/S) * 4/(S+12)

Use the distributive law in reverse ( a*b + a*c = a*(b+c), in this case a=1/S):

10(4+S)/S * 4/(S+12)

Multiply the fraction. Remember: a/b * c/d = (ac)/(bd):

40(4+S)/(S(S+12))

And that's the result you gave.

Answer 3

Loiuse and Pascal answered you well and you should reward one of them.

The "s" is called the Laplace operator and its an exponential transfer function. You'll learn this later. You'll also learn how to solve the equation fully by separating both denominator terms.

Laplace "s" (for the mathematicians, and normally "p" for us lesser mortals) is very useful. It allows us to model simple physical systems (such as a motor) so that we can design a control circuit, i.e. control the motor to do what we want it to do within a set of parameters (limits). The "S" equation defines a physical system in terms of frequency (0 to infinity Hz for example) and its a useful tool to be able to easily identify its stable environment, thus set its limits. Once you can resolve the "s" equations fully, you will tranform back into the time domain (dt, exp(-t), for example) where you will be able to visualise the model by plotting very interesting curves.

Yes, "s" equations go hand in glove with calculus, he he.

Good luck!

Answer 4

10x[ (4/S) + 1 ]x [ 4 / (S+12) ] = 10x [ (4+S)/S ] x [ 4 / (S+12) ]

= [ 10x (4+S) x 4 ] / [ S x (S+12) ] = [ 40x (4+S) ] / [ S x (S+12) ]

Answer 5

[40/(4+s)][s(s+12)]
40/[s(s+12)(s+4)]

Answer 6

S=-4, it is still the school holidays?

Answer 7

The maths is easy, but understanding the purpose of your question sure isn't

Answer 8

40(4+1)*(4)
1600+40*4+S
1600+1600S
S=3200/12
S=266.7
S=267

Answer 9

@#$%^&*()_@#$%^&*()_@#$%^&*()@#$%^&*()_#$%^&*()$#%^&*($%^&*()$%^&*()%^&*()
Hope u find the answer.
To let you in on a secret-This is N O T Simple!
Here are the simple symbols:
+
-
x
dividing
@@
J
*^^*
Good Luck!!!!!!1+1=2

Answer 10

Sorry im useless at maths.