Write the equation in standard form for the line that is perpendicular to the graph of y=5x+1 & has a y-intercept of 4
2006-08-13 12:46:01 · 5 answers · asked by oreowood14 2 in Education & Reference ➔ Homework Help
i am sorry but everyone here did NOT answer the question correctly. If it was a multiple choice question you all would have gotten 0, and if it was a short answer question, you might have received partial marks.
First of all, the slope of the new line is -1/5, and y-int of 4, so the answer of y = -1/5x + 4 is slope-intercept form, the question asks for STANDARD form, so the answer is x + 5y - 20 = 0
hope that helped
2006-08-14 09:26:16 · answer #1 · answered by jaymay2008 3 · 0⤊ 0⤋
The correct answer is y= -1/5 x + 4. Y = 4 when x= 0. (Y intercept) The slope of the original eqn. is 5. The slope of a perpendicular line is the opposite reciprocol. If you graph the two lines, you will see they are perpendicular.
2006-08-13 20:42:50 · answer #2 · answered by curious 3 · 0⤊ 0⤋
ok
4=5x+1
-5
4-5=x+1
4-5+x
-1=x
x=-1
2006-08-13 19:50:36 · answer #3 · answered by qwerty 4 · 0⤊ 0⤋
y = 1/5x + 4
i thinkk that's right.. 98.4% sure
2006-08-13 19:49:10 · answer #4 · answered by dolphini2007 2 · 0⤊ 0⤋
y=-5x-4
trust me on this
I AM A MATH GOD!
2006-08-13 19:51:47 · answer #5 · answered by Jake 2 · 0⤊ 0⤋