In a best of 3 sets mixed doubles tennis match, what is the least number of serves a man can make and be in the winning pair?
2006-08-13 12:05:36 · 5 answers · asked by freddiew 3 in Sports ➔ Tennis
Twelve. The least number of games would be 12 (6-0, 6-0), meaning that he would have to serve at least 3 service games. If he got his first serve in & won the point every time, he'd need 4 serves for each game he served . 3x4 =12.
2006-08-13 12:59:40 · answer #1 · answered by Dragon 7 · 0⤊ 0⤋
12
2006-08-13 14:25:43 · answer #2 · answered by im_cool 3 · 0⤊ 0⤋
12 serves - the woman serves first in the first set and they win 6-0. The man serves first in the second set, and has to serve 2 games when they win 6-0. It comes to 12 serves.
2006-08-13 12:58:32 · answer #3 · answered by globetrotter 2 · 0⤊ 0⤋
26
2006-08-13 12:11:24 · answer #4 · answered by echiasso 3 · 0⤊ 0⤋
24 serves, 12 for each set you win.
2006-08-13 12:09:35 · answer #5 · answered by Anonymous · 0⤊ 0⤋