Looking of an equation!!?

1 ⤊

Hi, I was wondering if anyone out there knew of an equation whose answer is a set of all real numbers between 1 and infinity.

2006-08-13 05:29:20 · 3 answers · asked by kaerukaiser 1 in Science & Mathematics ➔ Mathematics

|x-1| = x - 1

2006-08-13 05:40:34 · answer #1 · answered by Scott R 6 · 1⤊ 0⤋

If you need both 1 and infinity excluded (X>1 and X
log((2x-2)^2) = 2log(2x-2), or

log((ax-a)^2) = 2log(ax-a), where a is any real number > 0

2006-08-13 16:13:05 · answer #2 · answered by oldbutcrafty 2 · 0⤊ 0⤋

Well, you may do this: Solve in [1,+oo), x = x LOL

The first solution was pretty clever. You may express it so:

sqrt[(x-1)^2] = x-1

Ana

2006-08-13 16:48:57 · answer #3 · answered by Ilusion 4 · 0⤊ 1⤋