make a 3*3 matrix such that the sum of all the rows & colums should be equal to 15?

Answer 1

There's a cute book all about this called "Ben Franklin and the Magic Squares" by Frank Murphy that I use in my classroom.

Answer 2

2 7 6
1 5 9

4 3 8

Answer 3

As an expert in magic squares (certain, really!), the question you ask isn't a probability. you could't have any such sq. the position the products are all an similar (for instance, 5 and seven in straightforward words happen once on your numbers - so in straightforward words one row and in straightforward words one column could have a product divisible with the help of 5 and/or 7). Sum is problem-free, besides the undeniable fact that - you could really make up such squares your self, merely making an allowance for that the centre sq. could be 5, and all rows and columns could upload as a lot as fifteen. .

Answer 4

Assuming we do not repeat the nos and use only digits 1 - 9.
6 1 8
2 9 4
7 5 3
Feels great i cud do it !

Answer 5

if it's one of the puzzle in the rpg game, u have to work it out urself.
if u still got stuck, go to www.gamefaqs.com
................................................................................
........ ok, i'm a good guy:
2 9 4
7 5 3
6 1 8

have fun! don't forget to save it before u get to the next room!

Answer 6

The truth is 5s would fill all three rows and columns.