does a negative times a negative equal a positive?

Question

I always forget, so please tell me if I'm right and if I'm not please correct me...thanks!
- X - = +
+ X + = +
- X + = -

so, is that right?

Answer 1

yes you are right!

i have a little tip for you that may help you in remebering these easily. when two are of same opinion, things go positive - right? so when both are '+' or both are '-' the result is positive. but when, they are different, the result is negative.

i wish it may help!

Answer 2

There are a pair of techniques of thinking approximately this. utilising the selection line is a competent thank you to visualise it, in spite of the incontrovertible fact that it does not characterize a valid evidence. rather, we are able to artwork without delay with the definition of "detrimental" to coach why it incredibly is real. So what's a detrimental selection? nicely, if x is any beneficial selection, then -x is defined to be the selection that once extra to x provides us 0. for example, evaluate 3. as quickly as we upload -3 to it, we get 3 + (-3) = 3 - 3 = 0. Now, enable a and b be beneficial numbers. Then -a and -b are negatives. With a sprint algebraic manipulation, we are able to teach that their product is beneficial. enable's multiply them at the same time and upload (-a)(b): (-a)(b) + (-a)(-b) i will component out the -a, giving me -a(b - b) = -a(0) = 0. So, which means (-a)(b) + (-a)(-b) = 0 in spite of the incontrovertible fact that, submit to in techniques that a detrimental situations a great is a detrimental, so in that equation, we are able to replace (-a)(b) with -(ab): -(ab) + (-a)(-b) = 0 finally, upload ab to the two facets to cancel that -(ab) on the left facet: (-a)(-b) = ab and that's what we mandatory to coach. Now, in case you're curious as to why a great situations a detrimental is a detrimental, we are able to apply comparable suggestions. as quickly as lower back, enable a and b be beneficial numbers. enable's multiply a and -b, then upload ab and notice what happens: a(-b) + ab we are able to component out the a: a(-b + b) = a(0) = 0 So, we've a(-b) + ab = 0 Now, enable's upload -(ab) to the two facets to cancel with that ab on the left (it incredibly is the comparable component as subtracting ab from the two facets): a(-b) = -(ab) So, we've shown that a great situations a detrimental is a detrimental.

Answer 3

yes you are correct

Answer 4

ok

- times - is equal to positive answer
+ times + is equal to positive answer

+ times - is equal to negative answer
NOTE:( it could be a vise versa)

so your answer is correct

Answer 5

yes

Answer 6

yes

Answer 7

Yes you are correct. ^_^

Answer 8

yes..its correct

Answer 9

ABSOLUTELY CORRECT!!!!!!!!!!!!!
KEEP IT UP!!!!!
TRY TO LEARN:
(-2)+(-2)= -4
(-4)+(+2)= -2

Answer 10

yes, that is right