a+7d=37
a+11d=57
subtracting 4d=20 and so d=5
sudbstituting a=2
so the A.P. is 2,7,12,17,.......................
2006-08-12 23:09:21
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answer #1
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answered by raj 7
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Well, let's see
In an Arithmetic progression - as apposed to a geometric or "other" types of progressions- the difference between terms is determined by addition (or subtraction) of a nominally constant term....
If the 8th term is 37 and the 12th term is 57 the 4 terms in between caused the progression to increase by 20...that would seem to make each term increase by 5...
If that is true...to get the 8th term to equal 37...8 *(5) - 3
Check to see if that relationship holds true for 12
57 = 12 (5) - 3
seems to work
therefore
it seems like the arithematic sequence is
A.P. = 5n - 3
2006-08-12 23:18:14
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answer #2
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answered by Gemelli2 5
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Nth termof an AP : a + (n-1)d
8th term
a + 7d = 37 - - - -- - -- - (1)
12th term
a + 11d = 57 -- - - -- - -(2)
(2) - (1) -->
a + 11d = 57
-a - 7d = -37
= 4d = 20
d= 5
of d =5, then
a+ 35 = 37
a = 2
Therefore the AP is 2, 7, 12, 17, 22 .........
2006-08-14 07:50:17
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answer #3
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answered by M.S.N. 2
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nth term = (first term) + (common difference)*(n - 1)
x = a + d*(n - 1)
57 = a + 11d
37 = a + 7d
Subtract the two equations:
20 = 4d
d = 5
Now find the first term "a"
57 = a + 11*5
a = 2
Series is
2, 7, 12, 17, 22...
2006-08-13 14:14:49
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answer #4
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answered by Anonymous
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Amanda, I'd love to help you, but I don't have a clue as to what you're talking about. I'm sure there's a math site somewhere that can help you.
2006-08-12 23:09:38
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answer #5
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answered by Anonymous
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It's this junk that made me choose Accounting.
But I still have to deal with statistics which annoy me too.
2006-08-12 23:15:39
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answer #6
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answered by Jesse 4
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Come again?
2006-08-12 23:13:28
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answer #7
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answered by Anonymous
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DEAR-I COULD HELP U, BUT I DONT HAVE A CLUE WHAT U R SAYING........SORRY
2006-08-12 23:12:36
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answer #8
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answered by BUD 5
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35.67
hahahahaha!!!
2006-08-12 23:16:38
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answer #9
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answered by ann 1
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you find it.
2006-08-12 23:08:14
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answer #10
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answered by deleted 4
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