2006-08-12 21:24:37 · 10 answers · asked by karen p 1 in Science & Mathematics ➔ Physics
The acceleration experienced by a body during free fall towards earth due to the earths gravity only and neglecting any other factor is called the g force.
g = 9.8 m/sec square
2006-08-12 21:31:47 · answer #1 · answered by Genius__me!!!!!!!! 2 · 2⤊ 1⤋
You can google on f.x.
1 g in newton per kilogram
or
1 g * 2 ounces in atmosphere square feet
or whatever units you prefer.
In metric units, gravity accelerates an object by 9.82 meter per square second. This means that if you drop something it will have a speed of 9.82 meter/second after one second, 2*9.82 meter/second after two seconds etc.
In American units, the gravitation is one pound force per pound :-)
The gravitation varies with height, as the influence from the Earth becomes smaller as you get further away from the Earth's center. So if you want to loose weight, climb into the mountains :-)
It is also weaker the nearer you come to equator, which is partly because of the ellipsoid shape of Earth and partly because the centrifugal force, which contra-acts g, is strongest in the tropics.
But those local differences are very small.
2006-08-12 21:35:02 · answer #2 · answered by helene_thygesen 4 · 1⤊ 0⤋
youre kidding right? A g Force is equal to the acceleration of earths gravity at ground level.
why is it called a G force? The force (misuse of word though, more like acceleration) of GRAVITY.
2006-08-12 21:31:14 · answer #3 · answered by Kyle M 6 · 1⤊ 1⤋
Its 0.0034 G's
2014-06-10 19:35:58 · answer #4 · answered by almero1955 1 · 1⤊ 0⤋
By difinition, 1g....the scale used to measure acceleration of an object (g forces) is in multiples of the gravitational pull of the earth...i.e. if you weigh 100 lbs, and you pull four gee's, you feel as if you weigh 400 lbs...at six gee's you weigh 600, etc. tetc.
2006-08-12 23:02:00 · answer #5 · answered by nightwulf@verizon.net 1 · 1⤊ 0⤋
It's possible for sure
2016-07-27 06:55:19 · answer #6 · answered by ? 3 · 0⤊ 0⤋
For earth it is 9.8m/sec square and for our sun it is 394m/sec square.
2006-08-13 00:56:00 · answer #7 · answered by Anonymous · 1⤊ 0⤋
its the downward gravitational pull. g= 9.8m/sec^2
2006-08-12 23:12:43 · answer #8 · answered by Sikandar 2 · 0⤊ 0⤋
approximately 9.8 m/s²
2006-08-12 21:32:47 · answer #9 · answered by Chie 5 · 2⤊ 0⤋
It should be about 1g.
2006-08-12 21:33:31 · answer #10 · answered by iandanielx 3 · 1⤊ 0⤋