2C2H6 + 7O2 ---> CO2 + H2O ... How many moles?

Question

How many moles of CO2 would be produced from 56 moles of O2 according to the following balanced equation?

2C2H6 + 7O2 --> CO2 + H2O

Answer 1

the equation that you put up is not balanced!
this is the balanced equation:
2C2H6 + 7O2 --> 4CO2 + 6H2O

so with 7 moles of O2 you'd get 4 moles of CO2
hence with 56 moles of O2 you'd get:
56/7 x 4 moles of CO2 = 32 moles of CO2.

this is of course provided you have enough C2H6 to combust (16 moles of it to be exact).

Answer 2

2

Answer 3

since for every mole of O2 according to the balanced equation 1 mole of CO2 is prodcued therefore every moles of O2 divided by 7, every moles of C2H6 divided by 2, and every moles of H20 divided by 1 will in turn gives the moles of CO2 required, in terms of 56 moles of 02, 56/7=8moles of CO2 are produced further in terms of details the equation would look as such, this is all according to the balanced equation provided

28C2H6 + 56O2--------------- 8CO2 + 8H20,

look if you divide each term by the lowest term 8 variable within the equation it will result in the original equation you provided thereby stating that thse are only demetions upon the original scale of the equation for the production of greate quantities, in terms of the equation provided this doesn't work and there is a very good reason for this being that the balanced equation provided by you is wrong, look at the carbon atoms on both sides they are no equal to each other, it should really look like this

C2H6+ 3.5O2--------- 2CO2 + 3H2O

as such i am forced to repeat my answer with the new equation:

this is how chemistry mole conversion processes work:

whatever moles your trying to produce it into put on top of the moles of the particular substance you have of:

therefore Co2 moles over O2 moles=ratio of Co2 moles over ratio of O2 moles according to the coefficients provided in the true equation(again remeber use my corrected formula because your balancing was worng).

As such:

CO2/x=56=2/3.5(according to the coefficents in the balaced equation)

thereby giving CO2 moles=2/3.5 * 56=32 moles of CO2 would be required

Answer 4

First problem is that the equation is not balanced, so get the correct coefficients on the right side (left side is okay). Since 56 = 7 times 8, you multiply the CO2 coefficient thus determined by 8 to get the correct answer.

Answer 5

32

Answer 6

32

Answer 7

First balance the equation. 2C2H6 + 7O2 ==> 4CO2 + 6H2O Then use a mole-mole ratio to change moles of ethane into moles of oxygen. (4.50 mol C2H6)(7 mol O2/2 mol C2H6) = 15.8 mol O2 Do the same to find the amount of CO2 and H2O produced (4.50 mol C2H6)(4 mol CO2/2 mol C2H6) = 9.00 mol CO2 (4.50 mol C2H6)(6 mol H2O/2 mol C2H6) = 13.5 mol H2O

Answer 8

The equation is not balanced.

2C2H6 + 7O2 --> 4CO2 + 6H2O

ANS: 32 MOLES

Answer 9

Kish gave a perfect answer-even included the posibility of limiting reactant quantities... 2 thumbs up!

Answer 10

that's not balanced at all! but according to that equation it would be 8.