A rectangular box has dimensions 1 1/2 feet x 2 feet x 3 feet. What is the length of the longest object that can be put in the box, if the object can be placed in any position?
A. 3.6 feet
B. 3.9 feet
C. 6.5 feet
D. 15.25 feet
2006-08-12 16:17:17 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
3.9, assuming an object that is very thin and rigid.
This is the distance between the lower left back corner and the front right top corner. You get it by taking all the dimensions, sqauring them, adding them, and taking the square root of that total. In this case, it is 3.905124... so 3.9 is close enough.
2006-08-12 16:23:50 · answer #1 · answered by Vincent G 7 · 0⤊ 0⤋
it depends on the objects shape. If it is a pencil, or something like that, you can put it following the box diagonal. If it is a rope, it can be way longer, etc
Ana
2006-08-12 23:23:23 · answer #2 · answered by Ilusion 4 · 0⤊ 0⤋
Try using the pythagorean theorem for your homework.
2006-08-12 23:19:36 · answer #3 · answered by Anonymous · 0⤊ 0⤋
If straight 3.6
2006-08-12 23:22:05 · answer #4 · answered by crownvic64 4 · 0⤊ 0⤋
D... if i can coil it around and around. you did say, "object can be placed in any position".
2006-08-12 23:20:53 · answer #5 · answered by Friendly Neighbor 5 · 0⤊ 0⤋