im not sure how to distribute the square to the function
2006-08-12 12:19:48 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
f(x) = 3x^2 - x + 2
f(a) = 3a^2 - a + 2
f(a)^2 = f(a) * f(a)
= (3a^2 - a + 2) * (3a^2 - a + 2)
= 9a^4 - 3a^3 + 6a^2 - 3a^3 + a^2 - 2a + 6a^2 -2a + 4
= 9a^4 - 6a^3 + 13a^2 - 4a + 4
2006-08-12 12:35:41 · answer #1 · answered by Pablo Fanques 3 · 2⤊ 0⤋
[f(a)]^2 = (3a^2 - a + 2)^2
=(3a^2 - a + 2) * (3a^2 - a + 2)
Multiply each term of the first factor by the whole second factor:
(3a^2)*(3a^2 - a + 2) - (a)*(3a^2 - a + 2) + (2)*(3a^2 - a + 2)
=(9a^4 - 3a^3 + 6a^2) - (3a^3 - a^2 + 2a) + (6a^2 - 2a + 4)
Now regroup the terms:
(9a^4) + (-3a^3 - 3a^3) + (6a^2 + a^2 + 6a^2) + (-2a - 2a) + (4)
= 9a^4 - 6a^3 + 13a^2 - 4a + 4
2006-08-12 13:35:54 · answer #2 · answered by Anonymous · 0⤊ 0⤋
f(x) = 3x^2 - x + 2
(f(a))^2 = (3a^2 - a + 2)^2
(f(a))^2 = (3a^2 - a + 2)(3a^2 - a + 2)
(f(a))^2 = 9a^4 - 3a^3 + 6a^2 - 3a^3 + a^2 - 2a + 6a^2 - 2a + 4
(f(a))^2 = 9a^4 - 6a^3 + 13a^2 - 4a + 4
2006-08-12 15:46:24 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
your'e looking at the problem the wrong way, try distributing the function to the square.
2006-08-12 12:29:59 · answer #4 · answered by Anonymous · 0⤊ 0⤋
f(a) = 3a^2-a + 2
[f(a)]^2 = f(a)*f(a) =9a^4 -6a^3+13a^2-4a+4
2006-08-12 12:24:24 · answer #5 · answered by a_liberal_economist 3 · 1⤊ 0⤋
The answer is x=4, a=2f
DUH
2006-08-12 12:33:10 · answer #6 · answered by Katy 1 · 0⤊ 1⤋