Pump A can fill a tank in 5 minutes while pump B can fill a tank in 10 minutes.?

Question

How long will it take to fill the tank if both are working together?

Answer 1

Well, do this.

Pump A takes 5 minutes to fill the whole tank, so in 1 minute, 1/5 of the tank is full.

Pump B takes 10 minutes to fill the whole tank, so in 1 minutes, 1/10 of the tank is full.

Let x equal the time it takes them to fill it together.

Multiply the time together by each separate time and add them.

x / 5 + x / 10 =

Now, what should it equal? Well, you want the pumps to fill the tank completely, right? So, let it equal 1.

x / 5 + x / 10 = 1

Now, solve. Multiply the entire equation by 10 to remove fractions.

10(x / 5 + x / 10 = 1)
2x + x = 10
3x = 10
x = 10/3 minutes or
3 & 1/3 minutes, or
3 minutes & 20 seconds.

Answer 2

Some have given the correct answer but not explained this problem properly.

You need to form some equation in terms of time. So, find out how much of the tank each pump can fill in t minutes:

Pump A: Takes 5 minutes to fill 1 tank.
Therefore by proportion, Pump A fills t/5 parts of 1 tank. Similarly, Pump B fills t/10 parts of 1 tank. So now we have t/5 parts and t/10 parts and want to know what t must be so that we have 1 full tank. Thus,

t/5 (parts of tank)+t/10 (parts of tank) = 1 (full tank)

This results in t= 3 and 1/3 min. So it will take 3 minutes and 20 seconds to fill 1 tank if both pumps are working together.

For these kind of problems you need to always identify what you will end up equating, i.e. time, tank capacity, rate, etc.

Answer 3

It would take 7.5 minutes. Pump A will fill half the tank in 2.5 minutes, while Pump B will fill the other half in 5 minutes. Add those together and you get 7.5 minutes.

Answer 4

3 minutes, 20 seconds.

Both pump for x minutes. A pumps T gal/5 min; B pumps T gal/10 min.

x/(5/T) gal + x/(10/T) gal = T gal

xT/5 + xT/10 = T

x/5 + x/10 = 1

2x + x = 10

x = 3 1/3 min = 3 min 20 sec

Answer 5

Pump A: 1 [job] / 5 [min]
Pump B: 1 [job] / 10 [min]

Togther:

1 / 5 + 1 / 10
= 2/10 + 1/10 = 3 [job] /10 [min]

So, number of minutes for the cooperating pumps =
1 [job] / 3 [job] /10 [min]
=1 [job] * 10 [min] / 3 [job]
=3.33 minutes
or 3 minutes 20 seconds

Answer 6

Together, they pump 1.5 tanks in 5 minutes (I assume they are filling the same size tank). Do some arithmetic....

The answer is .6666666..... of 5 minutes = 3 1/3 minutes

Answer 7

Rate of pump A: 0.2 tank/minute
Rate of pump B: 0.1 tank/minute

Just add the two rates and convert tanks per minute into minutes per tank; that will get you the answer for your question.

Answer 8

It all depends on the law of generic pump diagnostics if one pump was to fail because of a faulty generic flange suppression it would render the whole experiment useless and would have to be reviewed by some one with more experience in pumps like nike.

Answer 9

a=a
b=2a
If they are going to work together it would take them 7.5 minutes
speed is just the same so
if a is the only one it will take 5mins. to filled 1/3
if they work together they would filled 2/3 of the tank for five mins.
they will consume 2.5mins. tofilled 1/3
so 5 + 2.5 =
7.5 mins.

Answer 10

time taken with the help of a = 5 min time taken with the help of b = 10 min artwork dine with the help of a in 0ne minute = a million/5 of the total artwork artwork carried out with the help of b in a million minute = a million/10 of the total artwork at the same time as both pums artwork togethetr a million/time taken = a million/2 +a million/10 = (2+a million)/10 ths time taken = 10/3 = 3.33 minutes!have a delightful day:D