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Cu(NO3)2 + 3 H2O = NaHCO3

2006-08-11 15:06:23 · 6 answers · asked by rcpaden 5 in Education & Reference Homework Help

I am trying to balance a mixture between Copper nitrate and sodium bicarb.
Copper nitrate is Cu(NO3)2
Sodium Bicarb is NaHCO3
right?

2006-08-11 15:20:52 · update #1

6 answers

nope something is wrong...

you have different elements on each side of the equation... you cannot have that... you have N ( nitrogen) on the left and Na (sodium) on the right, Cu ( copper ) on left C (Carbon) on right...


EDIT OK now I can help you...

Cu(NO3)2 + NaHCO3

first you need to do the double replacement...

Cu(NO3)2 + NaHCO3 -------> Cu(HCO3) + NaNO3


then check for the cation ion charge balance...
Cu +2, NO3 -1 so that makes the Cu(NO3)2
Na +1, HCO3 -1 so that makes NaHCO3
Cu +2, HCO3 -1 so that makes Cu(HCO3)2
Na +1, NO3 -1 so that makes Na NO3

so re write with the cation/anion balanced...


Cu(NO3)2 + NaHCO3 -------> Cu(HCO3)2 + NaNO3
now balance from left to right each element... you start with

Cu.....1------> 1
N.......2------> 1
O......9------->9
Na.....1------->1
H.......1------->2
C.....1----->2

so now youhave to ad the LARGE numbers in front to balance...

start with the N's and balance it... by adding a 2 in front of the NaNO3 change everything in the balance accordingly
Cu(NO3)2 + NaHCO3 -------> Cu(HCO3)2 + 2 NaNO3
Cu.....1------> 1
N.......2------> 2
O......9------->12
Na.....1------->2
H.......1------->2
C.....1----->2

Now balance the H's by adding a 2 in front of NaHCO3...change everything in the balance accordingly
Cu(NO3)2 + 2 NaHCO3 -------> Cu(HCO3)2 + 2 NaNO3
Cu.....1------> 1
N.......2------> 2
O......12------->12
Na.....2------->2
H.......2------->2
C.....2----->2
each element balances so balanced equaltion is:
Cu(NO3)2 + 2 NaHCO3 -------> Cu(HCO3)2 + 2 NaNO3


hope it helps... :)

2006-08-11 15:09:41 · answer #1 · answered by Charity 3 · 3 0

You have no sodium (Na) or carbon (C) on the left (reaction side) and no nitrogen (N) or copper (Cu) on the right (product side). You either left something out, typed it wrong, or you messing with us, because this reaction is impossible. You can't get an element out that you don't put in!

2006-08-11 22:13:59 · answer #2 · answered by atwil 5 · 0 0

I agree with Charity. I thought each side of the equation should have some like terms in order to cancel each other out, but I could be wrong.

2006-08-11 22:12:17 · answer #3 · answered by rocketpop19 1 · 0 0

All chemical equations can be balanced. The balanced amount's may just be incredably large. Email me if you need help balancing it.

EDIT:::

Having just actually looked at the question, it cannot be balanced. Different elements.

2006-08-11 22:08:52 · answer #4 · answered by Teenage Metamorphmagus 234 2 · 0 0

no this equation can't be balanced.

2006-08-11 22:12:51 · answer #5 · answered by thunderwear 4 · 0 0

please write the formula in the correct terms Na...?

2006-08-11 22:12:14 · answer #6 · answered by Anonymous · 0 0

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