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I have this homework problem that asks about a triangle labled ABC. A to C is 150 meter C to A is at 87degrees and 30 feet. How do I do this?

2006-08-11 14:54:31 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

c^2 = a^2 + b^2 - 2ab(cos(C))

2006-08-11 16:49:00 · answer #1 · answered by Sherman81 6 · 0 0

hey dude clarify your question

A to C = 150 meter
C to A = 87 degress and 30 ft???? HOw could it be???

2006-08-11 22:07:12 · answer #2 · answered by cooler 2 · 0 0

http://www.csgnetwork.com/trigtriformulatables.html

2006-08-11 22:05:32 · answer #3 · answered by Nick Name 3 · 0 0

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