2006-08-11 11:49:33 · 5 answers · asked by Cassandra H 1 in Science & Mathematics ➔ Mathematics
s^4 t^4/r^5; s≠0, t≠0.
2006-08-11 11:57:19 · answer #1 · answered by Pascal 7 · 0⤊ 0⤋
When the bases are the same, add the exponents in the numerator, and subtract the exponents in the denominator. So:
(Mid-step) : r^-3-2 s^5-1 t^2-(-2)
answer: r^-5 s^4 t^4
Further info: since the exponent for r is negative, you can make it positive in the denominator. Also on t, when subtracting a negative number, you add. 2+2 = 2-(-2)
2006-08-11 19:16:08 · answer #2 · answered by Freeway 2 · 0⤊ 0⤋
How many factors of r do you have? -3 in the numerator means three in the denominator. 2 in the denominator then gives a total of 5 in the denominator.
How many factors of s do you have? 5 in the numerator and one in the denominator, so a total of 4 in the numerator.
How many factors of t do you have? 2 in the numerator and -2 in the denominator which means a total of 4 in the numerator.
SO you've got: s^4t^4/r^5 or (st)^4/r^5 or (st/r)^4/r
whichever you think looks "simplest."
2006-08-11 18:58:21 · answer #3 · answered by Benjamin N 4 · 0⤊ 0⤋
r^-5 s^4 t^4
2006-08-11 19:40:05 · answer #4 · answered by Ali 2 · 0⤊ 0⤋
(r^-3s^5t)/(r^2st^-2)
r^(-3 - 2) * s^(5 - 1) * t^(1 - (-2))
r^(-3 + (-2)) * s^4 * t^(1 + 2)
r^(-5) * s^4 * t^3
ANS : (s^4t^3)/(r^5)
2006-08-11 19:39:26 · answer #5 · answered by Sherman81 6 · 0⤊ 0⤋