4a+5b+7c= 13
a:2
b:1
c:0
a+b+c=3
(but i don't understand this one : 4a+3b+c?? )
who cares, i got my 2 points :))
2006-08-11 10:51:36
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answer #1
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answered by justforfun 2
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a= -1
b=2
c=1
2006-08-11 16:16:11
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answer #2
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answered by Lyney 2
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I'm going to really go out on a limb with this one, and I'm gonna say
NONE OF THE ABOVE?!?!?!
Actually, as I went over it again, I see:
a+b+c =3 1/4 or 3.25 making a= (-6 3/4), b= (15), and c=(-5)
After getting rid of the 4a, I multiplied the 5 and 3 of the two different (b)s to get 15, and 15 times what would get me a neg.number that would go well with the higher multiple of 7 with the two different (c)s. The rest is elementary.
This is all assuming that you are making both equation equal each other, and both also equal 13!!
2006-08-11 10:56:24
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answer #3
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answered by Brucie Boy 3
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You are almost certainly missing some information here. You need to know at least what the second equation, 4a+3b+c, equals.
When you ask, "Please tell me the steps and the answer," you make it seem as though you need this information for a homework assignment. Be aware that copying an answer from this website constitutes cheating.
2006-08-11 11:10:55
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answer #4
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answered by llemma 3
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Well, your second sum doesn't have a value.... 4a+3b+c= ??
Anyway... you multiply the second with minus "-", add the two, and then have an ecuation with 2 unknowns. That's pretty easy to resolve.
2006-08-11 10:47:55
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answer #5
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answered by kiralyvlad 2
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Just add equation 1 and 2 and u get 8(a+b+c)=13+whatever second equation equates to, lets say "Y"
Divide the above equation by 8 and u get a+b+c=(13+Y)/8
2006-08-11 10:52:22
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answer #6
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answered by naika_m 2
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a+b+c= 2 points
2006-08-11 10:50:40
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answer #7
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answered by ZenTurkey 4
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First, what is 4a+3b+c=?
2006-08-11 10:46:53
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answer #8
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answered by Anonymous
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8a+8b+8c=13
2006-08-11 10:57:56
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answer #9
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answered by angel_babii 3
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yeah, hmmm sorry I missed this day in school, I went to the beach ! but good luck
2006-08-11 10:44:54
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answer #10
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answered by Big R 6
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