English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

and is perpendicular to the line with equation y = -3x +1.

2006-08-11 10:16:39 · 5 answers · asked by wicked 1 in Science & Mathematics Mathematics

5 answers

y = 1/3x + 5

2006-08-11 10:20:00 · answer #1 · answered by Brian 3 · 0 0

y = mx + b

y = -3x + 1 (slope is -3, y-intercept is 1)

Perpendicular lines have slopes of -1/m with respect to each other.

Answer : y = 1/3x + 5 (slope is 1/3, y-intercept is 5)

2006-08-11 17:21:31 · answer #2 · answered by Arkangyle 4 · 0 0

The equation of line is given by :

y= mx + c

where m=slope of the line
c = y-intercept

Now since we dont know slope, we have to find it first.

we can find that from the line perpendicular to it(given)
y=mx+c
y=-3x+1 (given)

so the slope of given equation is -3
=======================================
the slope of line u r finding will be m=1/3

so the equation u want to find is y=1/3x + 5

2006-08-11 17:49:15 · answer #3 · answered by Da Sahar SToRaY 2 · 0 0

y=mx+b, b is the intercept = 5 and m is the slope. Slope is rise orver run say, -3/1 so perpendicular is m = 1/3.

2006-08-11 17:22:03 · answer #4 · answered by bubsir 4 · 0 0

The slope must be the negative reciprocal of -3, so it would be 1/3
Slope = rise / run = (y1-y2) / (x1-x2)
1/3 = (y - 5) / (x - 0)
Cross-multiplication:
3(y-5) = 1(x-0)
3y - 15 = x
3y = x + 15
y = 1/3x + 5

2006-08-11 17:29:46 · answer #5 · answered by WaterfallOfDestiny 7 · 0 0

fedest.com, questions and answers