2006-08-11 08:38:55 · 8 answers · asked by rcpaden 5 in Education & Reference ➔ Homework Help
What you have there is a quadratic equation. Where a, b, and c are variables that represent integers. The solutions of x can be found using the quadratic formula. x = (-b + or - sqrt[b^2 -4ac])/2a
so if you had a equation
x^2 + 2x - 1=0
a = 1
b = 2
c = -1
the solution is -1 + or minus sqrt(2)
2006-08-11 08:46:42 · answer #1 · answered by anonomous 3 · 1⤊ 0⤋
they are all 0's
2006-08-11 15:43:59 · answer #2 · answered by plasticrooster 2 · 0⤊ 0⤋
the coefficients of the variables.... they could be any number..
like this... 5x^2+6x+7=0..... a=5, b=6, and c=7
2006-08-11 15:42:39 · answer #3 · answered by Einstein 3 · 1⤊ 0⤋
a b and c can be a lot of things that is the basic set up of a quadratic equation.
2006-08-11 15:41:45 · answer #4 · answered by Anonymous · 0⤊ 0⤋
x = [-b +/- sqrt(b^2-4ac)]/2a
solve for a, b, or c as you like, realizing that each of their values will be dependent on the others.
2006-08-11 15:45:06 · answer #5 · answered by jimvalentinojr 6 · 0⤊ 0⤋
Please not math I worked all day all I want to do is answer none numbers questions!!! A,B,C =0
2006-08-11 15:43:56 · answer #6 · answered by Anonymous · 0⤊ 0⤋
math
2006-08-11 15:40:55 · answer #7 · answered by Anonymous · 0⤊ 0⤋
A+B= AB C?
2006-08-11 15:41:50 · answer #8 · answered by Anonymous · 0⤊ 0⤋