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Write the equation of the line which has y-intercept (0, 5) and is perpendicular to the line with equation y = –3x + 1.

2006-08-11 07:49:11 · 8 answers · asked by sistermoon 4 in Education & Reference Homework Help

8 answers

y= 1/3x+5... when you're finding a line perpendicular to another you find the negative reciprocal of the slope..you already know the y intercept is 5 therefore you know the slope is the negative reciprocal of -3 or 1/3 and it crosses the y intercept at 5.

2006-08-11 07:53:51 · answer #1 · answered by GC 4 · 1 0

Since it is perpendicular to the said line its slope is 1/3. Thus (y-5)/(x-0) = 1/3. Hence y = x/3 +5 is the desired equation.

Note: In solving this I used two main facts. First if lines L1 and L2 are perpendicular than their slopes m1 and m2 are related by: m1 = -1/m2. Furthermore I used the point slope formular to get the equation of the line.

2006-08-11 14:54:45 · answer #2 · answered by Agbanusi I 2 · 0 0

y=1/3x+5

2006-08-11 14:54:09 · answer #3 · answered by Anonymous · 0 0

slope of give equation(m1)= -3
slope of required equation is m2 say then m1*m2= -1
-3*m2= -1
m2=1/3
so equation of required line is y=1/3 x+5
or 3y=x+15

2006-08-11 15:26:24 · answer #4 · answered by flori 4 · 0 0

I think you should pay more attention in class if you have all of these questions.

2006-08-11 14:52:04 · answer #5 · answered by rebecca 3 · 0 0

pay attention or look it up rather than people telling you

2006-08-11 14:54:52 · answer #6 · answered by Erich J 2 · 0 0

Go here
http://www.tutorvista.com/index.php?a=a

2006-08-11 14:53:23 · answer #7 · answered by captianpr 4 · 0 0

helpmeinmath@sbcglobal.net

2006-08-11 14:56:20 · answer #8 · answered by Princess_777 2 · 0 0

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