Think of it like a river that branches into several rivers then come back together to form a single river again. Voltage is the equivalent of the amount of water available, current is the speed of the water. Not a perfect analogy, but it gets the idea across.
2006-08-11 07:48:18
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answer #1
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answered by Will 6
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Voltage being a "measure of push available" is more of an analogy. Can you clarify your question a bit?
If I am understanding it right, you are asking why the voltage across two branches of a parallel circuit is the same. The answer is that, if you 'move the wires' a bit, you'll see that the branches all come out of the same 'point' on each side (hard to explain without a picture). The voltage can't be two different values at the same point. Does that make sense?
2006-08-11 07:01:22
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answer #2
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answered by Davon 2
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The voltage does change. In fact the voltage changes by the same amount over all branches of a parallel path. It has to the paths start and end together. What is different is the current. It is divided by the relative resistances. More goes the easier way, the way with least resistance.
2006-08-11 07:04:11
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answer #3
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answered by TC 3
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Look up Kirchoff's Voltage Law in an electrical engineering text.
Given the voltage difference between any two points in a circuit, Ohm's Law (E=IR) lets you calculate the current that would flow through any resistance connected to those two points, independent of anything happening in the rest of the circuit. In a real circuit, of course, connecting a resistance will likely affect the voltage.
2006-08-11 18:54:17
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answer #4
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answered by Frank N 7
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LIke the water analogy, voltage is more like pressure.
Voltage is formally the amount of energy it to raise displace charges. Since energy tends to decrease naturally, a voltage difference will tend to "push" charge through whatever the leads touch.
The analogy is a bit simple, but I do recall explaining to others that voltage sources are like "current pushers."
2006-08-11 08:44:46
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answer #5
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answered by Captain_Ahab_ 3
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Because each leg of the circuit has equal "potential"
2006-08-11 06:57:52
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answer #6
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answered by Anonymous
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Why should it change?
2006-08-11 06:54:23
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answer #7
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answered by Dr M 5
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