They've added some talent and won't miss Daunte Culpepper I don't think,
2006-08-11 06:16:30 · 18 answers · asked by brookings88 2 in Sports ➔ Football (American)
The Bears will win that division, but Minnesota should have a decent year. They have a underrated RB, a QB that just wins games, and their Defense should be better (Cant get worse). They play in a mediocre division, Detriot will be much better this year and GB will be GB (shine a times, but mostly pathetic).
2006-08-11 06:58:08 · answer #1 · answered by Casual Traveler 5 · 0⤊ 0⤋
You got that right. Johnson isn't Culpepper. Johnson could actually read his receivers. Culpepper can't even read 'See Spot Run". And also, Johnson can hold on to the ball.
Koren Robinson isn't Randy Moss. True, but then again, he's still something special.
The Packers? Come on! Brett Favre is your quarterback. That would have been an advantage 9 years ago, but also 9 years ago, it was also cool to listen to the Spice Girls.
The Bears simply have no offense and now everybody knows what the Bears are about so they're going to aim for them.
But I can say this though, this season, it's great to have the Bears-Vikings rivalry off life support, especially since we're both favorites to compete for the division. The banter between Bear and Viking fans hasn't been like this since the 1980's.
2006-08-11 13:31:43 · answer #2 · answered by enigma_frozen 4 · 0⤊ 0⤋
Im going to say no and heres why,
True you want miss Culpepper, but you will still be missing that homerun deepthreat that you gave aaway whenver Randy Moss left. You also got wrid of Corey Chavious, and Bennett at running back. If chicago can get ther act together and score, they ar the team to beat in that division
2006-08-11 06:21:28 · answer #3 · answered by ijustcamehere4freefood 3 · 0⤊ 0⤋
No. Koren Robinson is no Randy Moss and Brad Johnson is no Daunte Culpepper. Plus, new coach, new system, no team chemistry. I think that they're better than the Packers and Lions, and will be second to the Bears.
2006-08-11 06:35:26 · answer #4 · answered by C. Note 2 · 0⤊ 0⤋
absolutely not! u know why? THE PACK IS BACK! heres' who the Vikings have...
my point exactly, NOBODY! they r a garbage team playing in a garbage division. theres no way they can win the division with another 4-12 season (although they might get close)!
here's my prediction: the pack wins the division 8-8 and the vikes come in last 5-11
2006-08-11 06:33:46 · answer #5 · answered by beatswheats 2 · 1⤊ 0⤋
They will come in second behind the Bears. The bears have the most returning starters at key postions that made for a pretty good team last year. I think the NFC Central this year will be Bears, Vikings, Lions and then Packers.
2006-08-11 06:23:34 · answer #6 · answered by butnozzle 2 · 0⤊ 0⤋
A lot of people say no, but I have to say probably not. With the new systems on both sides of the ball it will take a year. Go Vikings and prove everyone wrong, that is why they play the games!!!
2006-08-11 07:23:03 · answer #7 · answered by Injun 3 · 0⤊ 0⤋
with a view to make the playoffs you the two ought to win your branch,or be a wild card team. A wild card team is a team who would not win his branch yet has the superb checklist out of the the rest communities. The wild card team performs the communities that have gained there branch yet don't have the superb checklist and those 4 communities play one yet another and the winners play the two communities who've the superb checklist in there branch. notice the two communities with the superb checklist in there branch have a bye week whilst the different communities play.
2016-10-01 22:58:25 · answer #8 · answered by ? 3 · 0⤊ 0⤋
No stinking way. Weak at QB, untested at RB, only fair at WR. Both lines are good, LB so-so, secondary unknown. They are in a lousy division so they'll do ok, but not win the division.
2006-08-11 06:52:54 · answer #9 · answered by FatElvis 4 · 0⤊ 0⤋
Are You Kidding!!! How about 4-11 for the season! Yucko Team
Carolina looks like Super Bowl winners this season..
2006-08-11 06:19:32 · answer #10 · answered by Kevin J. B 1 · 0⤊ 1⤋