Genetic Problem?

Question

Can someone show me step by step how to solve this problem.

An individual with genotype Tu is crossed with another individual with geneotype Tt. The mode of inheritence in autosomal dominant.

What fraction of the offspring is expected to exhibit the recessive trait? Select one of the following.

A. NONE
B. ONE-FOURTH
C. ONE-HALF
D. THREE-FOURTHS
E. ALL

I appreciate the help!

I meant Tt on both! there is no Tu

Answer 1

B. One-Fourth. You can do a Punnett Square to diagram the scenario:

T t

T TT Tt

t Tt tt

I tried to do the Punnet square, but it won't work in this format (can't do a table).

T, t, T and t are the traits of the parents.
TT, Tt, Tt, and tt are the traits of the offspring. 1 offspring demonstrates the homozygous dominant trait (TT). 2 offspring demonstrate the heterozygous dominant trait (Tt) and 1 offspring demonstrates the homozygous recessive trait (tt).

Answer 2

The cross will be:
Tt X Tt
The offspring:
1/4 TT
1/2 Tt
1/4 tt
Since the inheritance is autosomal dominant, everyone with the T allele will have the dominant trait, whereas only 1/4 of the offspring will show the recessive trait t.

The answer is B.

Answer 3

firstly you are told this is autosomal dominant. This lets you exclude sex linked traits. The genotype is Ti, so we know that only two traits are present. We know that if an individual has the dominant allele, he will show the phenotype with only one while if it was a recessive trait then he would need two recessive alleles.

So we have T allele (dom) and i allele (rec)

Using punnet squares, we would write

parents .... Ti x Ti
alleles T & i . . . T & i

offspring (F1) one T from mum and one T from dad
or one T from mum and one i from dad
or one i from mum and one T from dad
or one i from mum and one i from dad

giving you offspring with TT, Ti, Ti, ii

The fraction that will display the recessive trait is therefore one quarter of the offspring. The rest will display the dominant trait, although only one will be true breeding.
ure welcome to email me if you are still stuck

truebreeding ie TT = homozygous dominant
both traits ie Ti = heterozygous

truebreeding ii = homozygous recessive

Answer 4

Alas, Tu and Tt doesn't make sense. Are you sure there isn't some sort of typo in the problem?

Answer 5

awesome question. Leah is in part best and on objective besides the undeniable fact that the bigger situation arises at the same time as in straightforward words one figure is a provider. In that scenario a container try will under no circumstances artwork and the breeder has merely carried out more effective to harm their breed with the help of passing on a mutation 50% of the time without danger of detecting it. that's totally actual of known sires who're used very many times and/ or with the help of use of guy-made insemination the position their genes are disseminated in an particularly intense frequency between something else of the inhabitants. "container" finding out is likewise from time to time referred to as "try" matings. that's an particularly negative and unacceptable approach for figuring out inherited themes even in the previous there have been any DNA checks available. Breeders will under no circumstances do away with inherited diseases with try matings for the easy reason that there are any such large type of mutations and... you could't continuously perceive those that are organizations. also, if a provider to provider try mating takes position then the prospect of manufacturing an affected animal is 25% so the prospect nonetheless exists that an affected heavily isn't made out of each mating, now to not prepare with the help of that element that's too overdue... so why blindly mate without understanding no matter if a mutation exists with the prospect of propagating more effective of an similar difficulty? it truly is a stupid frame of mind fantastically now at the same time as there are any such large type of DNA checks and wellbeing monitors available. the region is not merely with the scenario "what if both mothers and fathers are organizations of a recessive ailment" yet more effective so "what if in straightforward words one figure is a provider." that is at the same time as the region maintains to bypass undetected.

Answer 6

One Half I think because the recessive trait is half of the two individuals, since only one of them has it. Hope i helped!

Answer 7

D
3/4s

or

B 1/4

im thinking D though

Answer 8

simple B.