the width of a ractangle is 3 inches less than its width.?

Question

the area of the rectangle is 340 square inches. what are the length and the width of the ractangle?

Answer 1

I assume the width is 3 inches less then the length (not width).

Assume the width is x, then the length is 3 + x.

You have x * (3 + x) = 340
==> x^2 + 3x - 340 = 0
==> (x + 20)(x-17) = 0

So, x = 17 inches.

Answer 2

The width is actually 3 inches less than the length (length is always longer than width)

Call length "L"
Call width "W"

W = L - 3

Area = length * width = 340 inches^2
340 =(L)*(L - 3)
340 = L^2 - 3L
L^2 - 3L - 340 = 0

Use quadratic formula:

L = [ -(-3) +/- sqrt( (-3^2) - (4)(1)(-340) ) ] / (2)(1)
=[ 3 +/- sqrt( 9 + 1360) ] / 2
=[ 3 +/- 37 ] / 2
=20 or -17 inches

Since inches cannot be negative, L = 20 inches
and
W = L - 3 -----> W = 17 inches

Length is 20 inches
Width is 17 inches

Answer 3

If we take w to be the width and l to be the length...

--- w + 3 = l

--- w * l = 340
--- w (w+3) = 340 (substitution from the first equation)
--- w^2 + 3w = 340
--- w^2 + 3w - 340 = 0
--- (w-17)(w+20) = 0
--- w = 17 or -20

Since a width of -20 doesn't make much sense, we'll go with 17 for the width and 17+3 or 20 for the length.

Answer 4

The width is less than its width?

Let X be the length of the shorter side. X+3 is therefore the longer side. X * (X+3) = 340.

X^2 + 3X = 340
X^2 + 3X - 340 = 0
Factor:
(X + 20) * (X - 17) = 0
So X = -20 or 17. X cannot be -20, obviously, so X (the shorter side) is 17 inches. The longer side is X+3, or 20 inches.

Answer 5

Let the length be x and the width is then x-3

The problem says that

x*(x-3) = 340 So

x² - 3*x - 340 = 0 and solve the quadratic

(x-20)*(x+17) So x = 20 or x = -17

Since negative length doesn't make sense, x = 20 for the length and the width is 17.


Doug

Answer 6

Presuming you meant that the width of the rectangle is 3 inches less than its length.

x(x-3) = 340

x^2 - 3x - 340 = 0

x = 17, 20

Answer 7

the section (or sq. pictures) of a room is desperate via multiplying the dimensions (in feet) of the room cases its width (in feet). to illustrate: A room 10 feet huge and 20 feet long might have 10 feet x 20 feet = 2 hundred feet squared (or sq. feet) of section. In arithmetic courses they're going to attempt all the information of this concept via providing you with the dimensions each each now and then in feet (for one length) and yards (for the different length). That way you need to do slightly conversion to love words until now you do the easy multiplication. Be on the seem out for this concept... yet differently to make you workout that gray matter on your head is to enable you be responsive to that the width is 10 feet and the dimensions is 10 feet longer. So what do you multiply to get section? in case you probably did no longer fall for the trick, you will multiply 10 feet via 20 feet. See... all an issue of listening to what they say and "information the words." Have a advantageous day.

Answer 8

x^2-3x-340=0
(x-20)(x+17)=0
so length 20 in and width 17 in

Answer 9

w = l - 3

lw = 340
l(l - 3) = 340
l^2 - 3l = 340
l^2 - 3l - 340 = 0

x = (-b ± sqrt(b^2 - 4ac))/(2a)

x = (-(-3) ± sqrt((-3)^2 - 4(1)(-340)))/(2(1))
x = (3 ± sqrt(9 + 1360))/2
x = (3 ± sqrt(1369))/2
x = (3 ± 37)/2
x = (40/2) or (-34/2)
x = 20 or -17

w = 20 - 3 = 17

Length = 20 inches
Width = 17 inches

Answer 10

Whats a ractangle?