p^2+13p-30=0
for this the first thing you gotta do is to FACTORISE:
so,
(p + 15)(p - 2) = 0
from the equation above you can deduce that:
p + 15 = 0
or,
p - 2 = 0
therefore, p = -15 or 2.
as simple as that. good luck and have fun with math!
2006-08-11 04:46:17
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answer #1
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answered by Anonymous
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p^2 + 13p - 30 = (p + 15)(p - 2)
p = -15 or 2
2006-08-11 13:04:43
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answer #2
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answered by Sherman81 6
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-15 and +2 ...
here's how to solve it:
1st, you have to factor them out (i find this easiest for this type of equation; there are other two ways: completing the square and quadratic formula), so the new equation looks like this:
(p+15)(p-2)=0
then, to solve for p, let p+15=0 and p-2=0, since the two factors are under a multiplication operation, and 0 multiplied by anthing will be equal to 0.
so, the p=-15 and p=2 ...
2006-08-11 04:48:37
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answer #3
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answered by lune_ellise 3
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2 ^ 2 + 13 x 2 - 30 = 0
p = 2
2006-08-11 04:46:46
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answer #4
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answered by Kevin H 7
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p=*square root sign over30/13 divided by 2
2006-08-11 04:42:11
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answer #5
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answered by Mike Dub 3
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(p+15)(p-2)=0
so p=-15 or 2
2006-08-11 04:40:12
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answer #6
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answered by raj 7
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