2006-08-11 03:55:43 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x²(x + 3)
The coefficients (1 and 3) have nothing greater than 1 in common, so you can ignore them. Of the terms with variables, the smallest exponent of x is x². That's the only common factor to pull out of the expression.
x³ + 3x² = x²( __ + __ )
x² · x = x³, so the first blank should be filled by x.
x² · 3 = 3x², so the second blank should be filled by 3.
x³ + 3x² = x²(x + 3)
2006-08-11 04:01:47 · answer #1 · answered by Anonymous · 0⤊ 0⤋
x+6
2006-08-11 11:10:03 · answer #2 · answered by sriram r 1 · 0⤊ 0⤋
x^2(x+3)
2006-08-11 11:02:12 · answer #3 · answered by raj 7 · 0⤊ 0⤋
if you mean x3+3x2 without the expected proper notation it would be:
3x + 6x
9x
9 and x
if you mean x^3+3x^2 with the expect proper notation it would be:
x^2 and (x+3)
2006-08-11 11:02:14 · answer #4 · answered by questionallthings 2 · 0⤊ 0⤋
x3+3x2 = x2 (x+3)
2006-08-11 12:47:43 · answer #5 · answered by kecik_dws 2 · 0⤊ 0⤋
(x^2) (x+3)
2006-08-11 11:02:57 · answer #6 · answered by Brian D 5 · 0⤊ 0⤋
x^3 + 3x^2 = x^2(x + 3)
2006-08-11 20:17:06 · answer #7 · answered by Sherman81 6 · 0⤊ 0⤋
first factor out x2.
you'll get
(x2)(x+3)=0
x2=0
x+3=0
this will give you x = 0, -3
2006-08-11 11:03:18 · answer #8 · answered by Santos Lucipher 2 · 0⤊ 0⤋
x^2(3+x)
Always use ^ or ** to show powers when the editor does not have the ability to show as exponents.
2006-08-11 11:06:13 · answer #9 · answered by Barkley Hound 7 · 0⤊ 0⤋