More maths!?

Question

hello thanx for looking at this.
simplify:

Y to the power of 8 times Y to the power of 3?

m to the power of 9 divided by m to the power of 6?

this one seems really hard:
y to the power of 3 times y to the power of 11 divided by y to the power of 8?

thanx!! iam trying to figure exponent questions out.

Answer 1

1.y to the power of 11
2. m to the power of 3
3. y to the power of 6

Answer 2

Y^8 * Y^3 = Y^8+3 = Y^11.
m^9 / m*6 = m^9-6 = m^3.
y^3 * y^11 / y^8 = y^3+11-8 = y^6.

Answer 3

When Multiplying Numbers with exponent and the same base, you should add the exponents.

1. Y^8 X Y^3 = Y^8+3= Y^11

When Dividing numbers with exponent and same base, you should subtract the exponents.

2. m^9 / m^6 = m^9-6 = m^3

3. Y^3 X Y^11 / Y^8 =Y^3+11-8 = Y^14-8 =Y^6

Answer 4

ok. When multiplying exponents with the same base, always add the exponents together (ex. Y^8 * Y^3 = Y^11)
When dividing exponents with the same base, always subtract the eponents from eachother (ex. M^9/ M^6 = M^3)
Using this information, you can solve Y^3*Y^11/Y^8 in steps. Y^3*y^11= Y^14. Y^14/Y^8=Y^6.
Now for the why: If you write down Y^8 out on paper (that is, writing Y*Y*Y*Y*Y*Y*Y*Y) and then wrote Y^3 (Y*Y*Y) next to it, and then wrote * inbetween to signify multiplication, you would get Y*Y*Y*Y*Y*Y*Y*Y*Y*Y*Y, or Y^11 (this is just a visual to help you understand).
For dividing, if you write down M^9 (as in M*M*M.....) and then write M^6 underneath, then cross out all the common Ms and you are left with M^3.
Hope that helped!

Answer 5

Okay. You just need to know the rules of exponents. :-)

When multiplying two like bases that have exponents, like in your y^8(y^3), you ADD the exponents and keep the base.

So, in y^8(y^3), you would keep the y the same and add the exponents.

y^8 x y^3 = y^11

You know that multiplication and division are opposite functions, right? So, what's the opposite of addition? Right! Subtraction. So, when DIVIDING, you SUBTRACT exponents!

m^9 / m^6 = m^3

Now, you just have a mix of them together.

y^3 x y^11 / y^8

Okay, well it depends on how the equation was written. If it was written like this:

(y^3 x y^11) / y^8, then you multiply first, then divide. If it was written like this:

y^3 x (y^11 / y^8), in other words, the division was written as a fraction, then you divide first.

Let's do it both ways.

(y^3 x y^11) / y^8
y^14 / y^8
y^6

y^3 x (y^11 / y^8)
y^3 x y^3
y^6

Oh, lookie! You get the same answer either way. Anywho, sometimes it makes a difference, so watch for how the equation is written. If there's a fraction (division) written in, you have to do that part first!

Hope I was helpful.

Answer 6

General rule: if you are multiplying or dividing terms such as these in which the base (in this case, y) is the same, simply add or subtract the exponents.

y^8 * y^3 = y^(8 + 3) = y^11
m^9 / m^6 = m^(9 - 6) = m^3
y^3 * y^11 / y^8 = y^(3 + 11 - 8) = y^6

Answer 7

Y^8 x Y^3 = Y^(8+3) = Y^11

m^9 / m^6 = m^(9-6) = m^3

y^3 x y^11 / y^8 = y^(3+11-8) = y^6

Answer 8

1. Y to the power of 8 times Y to the power of 3?
add the exponents - answer y to the 11th power

2. m to the power of 9 divided by m to the power of 6?
subtract the exponents (numerator minus denominator) - answer y to the 3rd power

3. y to the power of 3 times y to the power of 11 divided by y to the power of 8
first in the numerator, add the exponents (y to 14th power), then subtract the exponents (numerator minus denominator) - answer y to the 6th power

Answer 9

y^8*y^3 = y^11
hint: add exponents in multiplication

m^9/m^6 = m^3
hint: subtract exponents in division

(y^3*y^11)/y^8 = y^14/y^8 = y^6
now put it all together!

Answer 10

Laws of exponents:

a^m * a^n = a^(m+n)

a^m / a^n = a^(m-n)

(a/b)^m = (a^m) / (b^m)

First problem

y^8 * y^3 = y^(8+3) = y^11

m^9 / m^6 = m^(9-6) = m^3

(y^3 * y^11) / y^8 = y^14 / y^8 = y^6

Got it?


Doug