scanf("%d%d",&a,&b) question is ? for we use "% " b4 either int orchar0r double or any else is it necessary.

Answer 1

You need to use the % before any output, it 'tells' the program that it's a data-type that your going to be outputting instead of the actual character

Answer 2

rachelle105210 is absoultely right .... How does this work ? ... Simply ... compiler prints the string btn commas " " ... when it finds % operator , it searches for the variables after commas , in ur case (a) ... It also checks if the type of this variable is the same tupe after % operator ... so if u wrote %d , a must be integer while if u wrote %s the variable must be string ... and so on .......
As a pesonal advice , use cout istead of printf and cin instead of scanf ... I'll write an example for u ...
printf("my age is %d and my name is %s",a,b);
// while a is an integer and b is a string , by using cout it will be ..
cout<<"my age is"< so u don't need to use % operator.

scanf("%d%d",&a,&b) ----> cin>>a>>b;

Answer 3

Your question is kinda blurry.

But I'm assuming the answer is: the % operator is universal the type is specified by the d character in your case, depending on your language. I also am assuming it's c/c++

You can find a list on what letter goes to what type in the compiler help.

Answer 4

You might want to consult your computing books for that. I would think it would return a zero value or error message since you haven't defined a, b and d as variables ?

Answer 5

Huh?

Answer 6

And your question is?

Answer 7

No, you're gay.