sixth of the life of speak spent in childhood twelveth is in youth and seventh of it is in bachelor....?

Question

five years after his marriage, his son was born but died 4 years before his own death at half of his age.... how old is speak died?

Answer 1

consider 7,12 and 6 the common number is 84. and
so
child = 14 years(0 to 14)
youth = 12 years (14 to 26)
bachelor=7 years(26-33) at 33 he would have got married.
at 42 he attained his half age
at 38 his son would have died.

Answer 2

I like awesomeash's answer, and I think that 84 was indeed the intended answer, but the problem should read "...died 4 years before his own death at half of his age AT THE TIME OF HIS OWN DEATH." Without this correction, the equation should be written (x/6 +x/7 + x/12)+(5)+((x-4)/2)+(4)=x, and Speak's age at death would be 65 1/3 years.

Answer 3

Let the age of the person when he died be x therefore
Age of son when he died =x/2
Life spent in childhood=x/6
Life spent in youth=x/12
Life spent in bachelor=x/7
From this we get
Age till marriage+time after marriage till son's birth+age of son + no. of years son died before Speak = Age at which Speak died
so we have
(x/6 +x/7 + x/12)+(5)+(x/2)+(4)=x
or
x - 75x/84 =9
therefore x=84years
Hence Speak died at the age of 84 years.

Answer 4

42

Answer 5

is it 84 years?