In"2NaOH(Sodium hydroxide)",What is the oxidation number of
Na(sodium)?
2006-08-10 23:29:11 · 9 answers · asked by star123 2 in Science & Mathematics ➔ Chemistry
Give Answer with explaination.
2006-08-10 23:30:29 · update #1
I can find out oxidation number of NaOH,But my problem with"2NaoH".
Here a number 2 comes before NaOH.
2006-08-11 00:12:47 · update #2
So,Find Out Oxidation number of "2NaOH",Not NaOH.
2006-08-11 00:14:08 · update #3
No matter what the coefficient of the compound be but the oxidation state is seen between the elements among the compound
here in NaOH oxidation number of sodium(Na+) is +1
its better we call oxidation state rather than oxidation number
this oxidation state doesnt depend on normality i.e concentration or coefficient in a chemical reaction
2006-08-11 05:06:24 · answer #1 · answered by anjs 2 · 0⤊ 0⤋
Na oxidation number:
+1
2006-08-10 23:38:46 · answer #2 · answered by AJ 2 · 1⤊ 0⤋
What Is The Oxidation Number
2016-10-07 11:08:09 · answer #3 · answered by swendsen 4 · 0⤊ 0⤋
O's oxidation number is -2 and H's oxidation number is +1... the sum must be zero... so... we say that the oxidation number of Na is "x"... x-2+1=0 => x=1
=> Na's oxidation number is +1
2006-08-14 03:48:49 · answer #4 · answered by white_fox362 2 · 0⤊ 0⤋
OK, let me explain. Sodium is in the IA group of the periodical table of elements by Mendeleev, so it has 1 (one) valent electron on its external electronic level. Next, it's more energetically favourable for it to give away its single electron to make its electronic configuration the same as neon Ne has, than to accept 7 electrons to obtain the electronic configuration of argon Ar. This defines its metallic properties. So sodium can have only a +1 oxidation number. In NaOH, too.
2006-08-11 00:08:08 · answer #5 · answered by Anonymous · 0⤊ 0⤋
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RE:
Oxidation Number?
In"2NaOH(Sodium hydroxide)",What is the oxidation number of
Na(sodium)?
2015-08-07 01:24:05 · answer #6 · answered by Melinde 1 · 0⤊ 0⤋
oxidation number of Na is still +1. It doesnt matter if you have 2 NaOH (2molecules of NaOH) or 100 NaOH.
2006-08-11 01:49:53 · answer #7 · answered by hi 2 · 0⤊ 0⤋
Na OH
Let the oxn state of Na be x.
Oxn state of O= -2, H= +1.
x+(-2)+1=0, becuz its a neutal compound.
This gives x=+1.
2006-08-10 23:50:46 · answer #8 · answered by uv 2 · 0⤊ 0⤋
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What is the coordination number for each of the following complexes? 1. [Fe(gly)2(H2O)2]+ ANSWER "6" ("gly" is bidentate) 2. [Ca(EDTA)]2- ANSWER "6" 3. [Zn(NH3)4]2+ ANSWER "4" 4. [Ag(NH3)2]NO3 ANSWER "2" What is the oxidation number of the central metal ion in each of the following complexes? 1. [NiCl2F2] 2- Oxid # is +2 2. [Cr(H20)2(NH3)4]3+ Oxid # is +3 3. Na[Cu(CN)2] Oxid # is +1
2016-03-27 01:50:38 · answer #9 · answered by Karen 4 · 0⤊ 0⤋
O.N.of alkali metals in their comps is 1.As Na is an alkali metal it's o.N.in NaOH is 1. O.N.doesn't change with no.of molecules.O.N.of Na in 2NaOH is same as in 1NaOH i.e. 1
2006-08-11 02:03:03 · answer #10 · answered by Rajchem 2 · 1⤊ 0⤋