divide r+5/r2+5r-14 by r2+4r-21/r-2?

Answer 1

First you need to flip the second fraction. Then you factor.

(r+5) * (r-2)
_________ ___________
(r-2) (r+7) (r+7) (r-3)

Then cancel the (r-2)'s and you get the answer:

(r +5)
___________
(r+7)(r+7)(r-3)

If that isn't the best answer, I don't know what is.

Answer 2

[r + 5/(r^2) + 5r - 14] / (r^2 + 4r - 21/r -2]

[6r - 14 + 5/(r^2)] / (r^2 + 4r - 2 - 21/r)

Multiply top & bottom by r^2

(6r^3 - 14r^2 + 5) / (r^4 + 4r^3 - 2r^2 - 21)

I did this long division and got r/6 + 19/18 plus a remainder, but I think you didn't write the problem correctly.

[Edit] Oops ... I see what you did. You left out the parentheses. The Best Saul got it for you. Only change I'd make in his solution is to put (r+7)^2 in the denominator.

Answer 3

When you divide by a fraction you multiply by its reciprocal:

(r + 5) / (r^2 + 5r - 14) divided by (r^2 + 4r - 21) / ( r - 2)
equals:

(r + 5) / (r^2 + 5r - 14) * (r - 2) / (r^2 + 4r - 21)
=(r + 5) / (r + 7)(r - 2) * (r - 2) / (r + 7)(r - 3)
=(r + 5)(r - 2) / (r + 7)(r - 2)(r + 7)(r - 3)
=(r + 5) / (r - 3)(r + 7)^2
=(r + 5) / (r - 3)(r^2 + 14r + 49)
=(r + 5) / (r^3 + 14r^2 + 49r -3r^2 -42r - 147)

=(r + 5) / (r^3 + 11r^2 + 7r - 147)

Answer 4

i know u have to flip the second part then factor then multiply...but its not worth doing right now...im not going to get anything out of it, even if i get ten pts it aint worth it =)