i cant figure out my homwork any help?

Question

here is the instructions tell whether the first number is divisable by the second number.
here are the promlems

#1- 527;3 #2- 1048 #3- 693;9

Answer 1

1. No. Just add the numbers together, and if it comes out as a multible of 3, the larger number is a multible of 3.
2. yes (I think...its 104, 8, right?) 80+24=104
3. Yes, 630 + 63 = 693

Answer 2

#1
because the sum of 5+2+7 = 14 which is not divisible by 3 therefore it is not divisible by 3
#2
Since the sum is 1+0+4+8=13 ,but 13 cannot be divisible by 3 therefore 1048 is not divisible by 3
# 3
since the sum 6+9+3=18 it is divisible by 9 therefore 693 is divisible by 9

Answer 3

To easily if any number is divisible by three, add up the digits. If this number is divisible by three, so is the original (EX, for #1, add up 5+2+7=14. 14 is not divisible by 3, so 527 is not either).

For nine, do this process twice. (EX, for #3, add up 6+9+3=18. Then add up 1+8=9. 9 is divisible by 3, so 693 is divisble by 9).

I don't know what your second problem is, but here is another hint: To tell if a number is divisible by 4, look only at the last two digits (tens and ones place). If this number is divisible by 4, the whole number is.

Answer 4

1.adding 5+2+7=14, not a multiple of 3 therefore not divisible by 3

2.second sum incomplete

3.6+9+3=18 is a multiple of 9 and so divisible by 9

Answer 5

Results:
~~~~~~~
1) abcd be a number.
abcd = a(1000) + b (100) + c(10) + d
= a(999+1) + b(99+1) + c(9+1) +d
= (ax999 + bx99 + cx9 ) +a + b + c + d
= 9(111a + 11b + c) +[ a + b + c + d ]
The first part is divisible by 3.
Hence if the second part is divisible by 3, the given number is divisible by 3.
The first part is divisible by 9.
Hence if the second part is divisible by 9 , the given number is divisible by 9.

2)abcd = ax1000 + bcd
1000 is divisible by 8.
Hence if bcd is divisible by 8, the given number is divisible by 8.

The proof works for numbers with more digits also.

Solution:
~~~~~~~
1) 5+2+7= 14;
1+4= 5;
5 is not divisible by 3.
Hence the given number is not divisible by 3.

2) I presume 104;8
104 is divisible by 8.

3)6+9+3 = 18;
1+8 = 9 which is divisible by 9.
Hence the given number is divisible by 9.

Answer 6

#1 - no because when you add 5+2+7, it does not come to a numer that is devisible by 3. (i.e. 14 is not a multiple of three)
#2 - yes, because the first three digits are divisible by 8
#3 - yes, because when you add 6+9+3, you get 18, which is divisible by 9.

One point of advice: you should memorize your divisibility test factors. It might come to haunt you if you don't.

Answer 7

I think you meant to ask whether the first number is divisible by the second number so the result is a whole number.
1.no
2.1048/?
3.yes

Answer 8

the first one no. You get a long decimal so it doesn't work

the second can't see the two numbers

the third yes 77 * 9=693. that makes 693 divisible by 9

Answer 9

u serious?!!!anyway, ill be a good sport.
#1. no
#2 only has 1 number so...
#3 yes

Answer 10

#3 Yes. (77)