2006-08-10 09:15:50 · 5 answers · asked by michelle_keefe 1 in Science & Mathematics ➔ Mathematics
reduce the fraction
2006-08-10 09:22:02 · update #1
(w+2)/(w-4)
2006-08-10 11:07:35 · answer #1 · answered by MollyMAM 6 · 0⤊ 0⤋
If I understand your question right.
w² + 5w + 6/w² - w - 12 = 0 (Multiply across by w²).
w^4 + 5w^3 + 6 - w^3 - 12w² = 0
w^4 + 4w^3 + 6 - 12w² = 0
w^4 + 4w^3 - 12w² + 6 = 0
2006-08-10 09:30:18 · answer #2 · answered by Brenmore 5 · 0⤊ 0⤋
the simple answer is 4w-6.... here's how...
w2+5w+6
w2-w-12 =
w2 cancels eachother out
5w-w+4w
+6-12= -6
put them together and you get 4w-6
2006-08-10 09:42:08 · answer #3 · answered by tito_loves_the_sun 2 · 0⤊ 0⤋
factoring=>(w+2)(w+3)/(w-4)(w+3)
cancelling out the w+3 the answer is w+2/w-4
2006-08-10 09:20:59 · answer #4 · answered by raj 7 · 0⤊ 0⤋
w^2 +5w+6/w^2-w-12
=w^2 +3w+2w+6/w^2 -4w+3w-12
=w(w+3)+2(w+3)/w(w-4)+3(w-4)
=(w+3)(w+2)/(w-4)(w+3)
=(w+2)/(w-4)
2006-08-10 09:50:30 · answer #5 · answered by flori 4 · 0⤊ 0⤋