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7 answers

7+7-7-7=0
[7+7]/[7+7]=1
[7/7]+[7/7]=2
[7+7+7]/7=3
[7x7]/[7+7]=3.5
[77/7]-7=4
7-[(7+7)/7]=5
(7x7-7)/7 = 6
7x(7-7)+7 = 7
(7x7+7)/7 = 8
7+[(7+7)/7]=9
(77-7)/7=10

2006-08-10 09:29:23 · answer #1 · answered by s_uperdave 3 · 0 1

(7+7 -7)/7 = 1

2006-08-10 16:20:14 · answer #2 · answered by YourDreamDoc 7 · 0 0

7+7-7-7 = 0

7/7 +7 - 7 = 1

plenty of ways

2006-08-10 16:19:31 · answer #3 · answered by AresIV 4 · 1 0

(7+7+7)/7 = 3

(77 / 7) - 7 = 4

7 - ((7 + 7) / 7) = 5

2006-08-10 16:28:33 · answer #4 · answered by Ralfcoder 7 · 0 0

7+7-7-7 = 0
(7+7)/(7+7) = 1
(7/7)+(7/7) = 2
(7+7+7)/7 = 3
4?
5?
((7*7)-7)/7 = 6
(7-7)/7+7 = 7
(7+7*7)/7 = 8
(7+7)/7+7 = 9
10?

2006-08-10 16:28:45 · answer #5 · answered by edmonddantes1986 2 · 0 0

7+7-7-7=0
(7+7)/(7+7)=1
7/7+7/7=2
(7+7+7)/7=3
77/7-7=4
7-(7+7)/7=5
(7x7-7)/7 = 6
7x(7-7)+7 = 7
(7x7+7)/7 = 8
7+(7+7)/7=9
77-7/7=10

2006-08-10 18:08:57 · answer #6 · answered by Stanyan 3 · 0 0

7-7+7-7 = 0
(7+7)/(7+7) = 1
7/7+7/7 = 2
(7+7+7)/7 = 3
77/7-7 = 4 (if thats allowed)
7-(7+7)/7=5
(7*7-7)/7 = 6
7*(7-7)+7 = 7
(7*7+7)/7 = 8
7+(7+7)/7=9

FIRST

2006-08-10 16:29:01 · answer #7 · answered by Anonymous · 0 0

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