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Okay, here is the problem: The area of the equilateral triangle is 20,000 cm^2. What formula can I use to find the perimiter of the triangle? And remember, I do not know the length of the altitude or anything. All I know is it's area!

And if you know of a site that explains the formula fully, please send a link to it!

2006-08-10 08:14:09 · 4 answers · asked by petwoip 1 in Education & Reference Homework Help

4 answers

area of equilateral triangle(A)= a^2
..........square root 3
4
20,000=a^2 * square root 3
.................................
4
80,000=a^2* 1.732
a^2 = 80,000
.............
1.732
a^2 = 46189.38 approx
a=214.92
so perimeter(P)= 4a
=4*214.92
=859.68 cm

2006-08-10 08:33:00 · answer #1 · answered by flori 4 · 0 1

Normally, the area of a triangle is half times base times the height. Now let the base be b which is equal for all three sides and let the height be h. the height, h is the straight line from one vertex to the middle of the opposite side to the vertex. This divides the triangle into two right angle traingles, each of them with sides b, h, b/2.
Now use Pythagoras' theorem with any of the right angled triangles gives: b^2 = h^2 + (b/2)^2.
=> h^2 = (3/4)*b^2
=> h = sqrt(3)/2 *b

Now we go back to the whole triangle,
Area = (1/2)*b*h
= (1/2)*b*[sqrt(3)/2]*b
= sqrt(3)/4 *b^2

Now you substitute the area you got and u get the side b.
Considering that it is equilateral and all side equal, then
Perimeter = 3*b
Doing this, your final answer should be something like 644.74cm.

You do not need a special formula for this. Simple geometry does the trick. Hope this helps.
Good luck!

2006-08-10 15:36:35 · answer #2 · answered by Stavi 2 · 0 2

OMG, that was a completely worthless answer Neil J.

To start with: let's label all the sides of triangle x, we know the angles are 60 deg.

A = b*h / 2

Draw the line that represents the height of the triangle (bisects the bottom side and is at a 90 deg angle.)

tan (angle) = opp side / adj side
tan (60) = h / 0.5x
tan (60) = 2h/x
h = tan (60) * x / 2
h = 0.866x (this ratio of the height to the base will be important.)

A = bh/2 = x * 0.866x / 2
A = 0.433x^2 = 20000 cm ^2

x = sqrt(20000/0.433) = 214.91 cm

perimeter = 3x = 644.74 cm

2006-08-10 15:37:31 · answer #3 · answered by Will 4 · 0 0

Triangles can be classified according to the relative lengths of their sides:

In an equilateral triangle all sides are of equal length. An equilateral triangle is also equiangular, i.e. all its internal angles are equal—namely, 60°; it is a regular polygon[1]
In an isosceles triangle at least two sides are of equal length. An isosceles triangle also has two equal internal angles (namely, the angles where each of the equal sides meets the third side). An equilateral triangle is actually also an isosceles triangle, but not all isosceles triangles are equilateral triangles[2]
In a scalene triangle all sides have different lengths. The internal angles in a scalene triangle are all different.[3]

Equilateral Isosceles Scalene

Triangles can also be classified according to the size of their largest internal angle, described below using degrees of arc.

A right triangle (or right-angled triangle, formerly called a rectangled triangle) has one 90° internal angle (a right angle). The side opposite to the right angle is the hypotenuse; it is the longest side in the right triangle. The other two sides are the legs of the triangle.
An obtuse triangle has one internal angle larger than 90° (an obtuse angle).
An acute triangle has internal angles that are all smaller than 90° (three acute angles).

Right Obtuse Acute
[edit]
Basic facts
Elementary facts about triangles were presented by Euclid in books 1-4 of his Elements around 300 BCE.

A triangle is a polygon and a 2-simplex (see polytope). All triangles are two-dimensional.

Two triangles are said to be similar if and only if the angles of one are equal to the corresponding angles of the other. In this case, the lengths of their corresponding sides are proportional. This occurs for example when two triangles share an angle and the sides opposite to that angle are parallel.

Using right triangles and the concept of similarity, the trigonometric functions sine and cosine can be defined. These are functions of an angle which are investigated in trigonometry.

In the remainder we will consider a triangle with vertices A, B and C, angles α, β and γ and sides a, b and c. The side a is opposite to the vertex A and angle α and analogously for the other sides.


A triangle with vertices, sides and angles labelledIn Euclidean geometry, the sum of the internal angles α + β + γ is equal to two right angles (180° or π radians). This allows determination of the third angle of any triangle as soon as two angles are known.


The Pythagorean theoremA central theorem is the Pythagorean theorem stating that in any right triangle, the area of the square on the hypotenuse is equal to the sum of the areas of the squares on the other two sides. If side C is the hypotenuse, we can write this as


This means that knowing the lengths of two sides of a right triangle is enough to calculate the length of the third—something unique to right triangles. The Pythagorean theorem can be generalized to the law of cosines:


which is valid for all triangles, even if γ is not a right angle. The law of cosines can be used to compute the side lengths and angles of a triangle as soon as all three sides or two sides and an enclosed angle are known.

The law of sines states


where d is the diameter of the circumcircle (the circle which passes through all three points of the triangle). The law of sines can be used to compute the side lengths for a triangle as soon as two angles and one side are known. If two sides and an unenclosed angle is known, the law of sines may also be used; however, in this case there may be zero, one or two solutions.

There are two special right triangles that appear commonly in geometry. The so-called "45-45-90 triangle" has angles with those angle measures and the ratio of its sides is : . The "30-60-90 triangle" has sides in the ratio of .

[edit]
Points, lines and circles associated with a triangle
There are hundreds of different constructions that find a special point inside a triangle, satisfying some unique property: see the references section for a catalogue of them. Often they are constructed by finding three lines associated in a symmetrical way with the three sides (or vertices) and then proving that the three lines meet in a single point: an important tool for proving the existence of these is Ceva's theorem, which gives a criterion for determining when three such lines are concurrent. Similarly, lines associated with a triangle are often constructed by proving that three symmetrically constructed points are collinear: here Menelaus' theorem gives a useful general criterion. In this section just a few of the most commonly-encountered constructions are explained.


The circumcenter is the centre of a circle passing through the three vertices of the triangle.A perpendicular bisector of a triangle is a straight line passing through the midpoint of a side and being perpendicular to it, i.e. forming a right angle with it. The three perpendicular bisectors meet in a single point, the triangle's circumcenter; this point is the center of the circumcircle, the circle passing through all three vertices. The diameter of this circle can be found from the law of sines stated above.

Thales' theorem states that if the circumcenter is located on one side of the triangle, then the opposite angle is a right one. More is true: if the circumcenter is located inside the triangle, then the triangle is acute; if the circumcenter is located outside the triangle, then the triangle is obtuse.


The intersection of the altitudes is the orthocenter.An altitude of a triangle is a straight line through a vertex and perpendicular to (i.e. forming a right angle with) the opposite side. This opposite side is called the base of the altitude, and the point where the altitude intersects the base (or its extension) is called the foot of the altitude. The length of the altitude is the distance between the base and the vertex. The three altitudes intersect in a single point, called the orthocenter of the triangle. The orthocenter lies inside the triangle if and only if the triangle is acute. The three vertices together with the orthocenter are said to form an orthocentric system.


The intersection of the angle bisectors finds the center of the incircle.An angle bisector of a triangle is a straight line through a vertex which cuts the corresponding angle in half. The three angle bisectors intersect in a single point, the incenter, the center of the triangle's incircle. The incircle is the circle which lies inside the triangle and touches all three sides. There are three other important circles, the excircles; they lie outside the triangle and touch one side as well as the extensions of the other two. The centers of the in- and excircles form an orthocentric system.





The centroid is the center of gravity.A median of a triangle is a straight line through a vertex and the midpoint of the opposite side, and divides the triangle into two equal areas. The three medians intersect in a single point, the triangle's centroid. This is also the triangle's center of gravity: if the triangle were made out of wood, say, you could balance it on its centroid, or on any line through the centroid. The centroid cuts every median in the ratio 2:1, i.e. the distance between a vertex and the centroid is twice as large as the distance between the centroid and the midpoint of the opposite side.


Nine-point circle demonstrates a symmetry where six points lie on the same circle.The midpoints of the three sides and the feet of the three altitudes all lie on a single circle, the triangle's nine-point circle. The remaining three points for which it is named are the midpoints of the portion of altitude between the vertices and the orthocenter. The radius of the nine-point circle is half that of the circumcircle. It touches the incircle (at the Feuerbach point) and the three excircles.





Euler's line is a straight line through the centroid (orange), orthocenter (blue), circumcenter (green) and center of the nine-point circle (red).The centroid (yellow), orthocenter (blue), circumcenter (green) and center of the nine-point circle (red point) all lie on a single line, known as Euler's line (red line). The center of the nine-point circle lies at the midpoint between the orthocenter and the circumcenter, and the distance between the centroid and the circumcenter is half that between the centroid and the orthocenter.

The center of the incircle is not in general located on Euler's line.

If one reflects a median at the angle bisector that passes through the same vertex, one obtains a symmedian. The three symmedians intersect in a single point, the symmedian point of the triangle.




[edit]
Computing the area of a triangle
Calculating the area of a triangle is an elementary problem encountered often in many different situations. Various approaches exist, depending on what is known about the triangle. What follows is a selection of frequently used formulae for the area of a triangle.[4]

[edit]
Using geometry
The area S of a triangle is S = ½bh, where b is the length of any side of the triangle (the base) and h (the altitude) is the perpendicular distance between the base and the vertex not on the base. This can be shown with the following geometric construction.


The triangle is first transformed into a parallelogram with twice the area of the triangle, then into a rectangle.
To find the area of a given triangle (green), first make an exact copy of the triangle (blue), rotate it 180°, and join it to the given triangle along one side to obtain a parallelogram. Cut off a part and join it at the other side of the parallelogram to form a rectangle. Because the area of the rectangle is bh, the area of the given triangle must be ½bh.


The area of the parallelogram is the magnitude of the cross product of the two vectors.[edit]
Using vectors
The area of a parallelogram can also be calculated by the use of vectors. If AB and AC are vectors pointing from A to B and from A to C, respectively, the area of parallelogram ABDC is |AB × AC|, the magnitude of the cross product of vectors AB and AC. |AB × AC| is also equal to |h × AC|, where h represents the altitude h as a vector.

The area of triangle ABC is half of this, or S = ½|AB × AC|.


Applying trigonometry to find the altitude h.[edit]
Using trigonometry
The altitude of a triangle can be found through an application of trigonometry. Using the labelling as in the image on the left, the altitude is h = a sin γ. Substituting this in the formula S = ½bh derived above, the area of the triangle can be expressed as S = ½ab sin γ.

It is of course no coincidence that the area of a parallelogram is ab sin γ.

[edit]
Using coordinates
If vertex A is located at the origin (0, 0) of a Cartesian coordinate system and the coordinates of the other two vertices are given by B = (xB, yB) and C = (xC, yC), then the area S can be computed as 1/2 times the absolute value of the determinant


For three general vertices, the equation is:


In three dimensions, the area of a general triangle {A = (xA, yA, zA), B = (xB, yB, zB) and C = (xC, yC, zC)} is the 'Pythagorean' sum of the areas of the respective projections on the three principal planes (i.e. x=0, y=0 and z=0):


[edit]
Using Heron's formula
Yet another way to compute S is Heron's formula:


where s = ½ (a + b + c) is the semiperimeter, or one half of the triangle's perimeter.

[edit]
Non-planar triangles
A non-planar triangle is a triangle which is not contained in a (flat) plane. Examples of non-planar triangles in noneuclidean geometries are spherical triangles in spherical geometry and hyperbolic triangles in hyperbolic geometry.

While all regular, planar (two dimensional) triangles contain angles that add up to 180°, there are cases in which the angles of a triangle can be greater than or less than 180°. In curved figures, a triangle on a negatively curved figure ("saddle") will have its angles add up to less than 180° while a triangle on a positively curved figure ("sphere") will have its angles add up to more than 180°. Thus, if one were to draw a giant triangle on the surface of the Earth, one would find that its angles were greater than 180°.

[edit]
References
^ http://mathworld.wolfram.com/EquilateralTriangle.html
^ http://mathworld.wolfram.com/IsoscelesTriangle.html
^ http://mathworld.wolfram.com/ScaleneTriangle.html
^ http://mathworld.wolfram.com/TriangleArea.html
[edit]
External links
Triangle Calculator - solves for remaining sides and angles when given three sides or angles, supports degrees and radians.
Napoleon's theorem A triangle with three equilateral triangles. A purely geometric proof. It uses the Fermat point to prove Napoleon's theorem without transformations by Antonio Gutierrez from "Geometry Step by Step from the Land of the Incas"
William Kahan: Miscalculating Area and Angles of a Needle-like Triangle.
Clark Kimberling: Encyclopedia of triangle centers. Lists some 1600 interesting points associated with any triangle.
Christian Obrecht: Eukleides. Software package for creating illustrations of facts about triangles and other theorems in Euclidean geometry.
Triangle constructions, remarkable points and lines, and metric relations in a triangle at cut-the-knot
Printable Worksheet on Types of Triangles
Compendium Geometry Analytical Geometry of Triangles
Area of a triangle - 7 different ways
Triangle definition pages with interactive applets that are also useful in a classroom setting. Math Open Reference
Proof that the sum of the angles in a triangle is 180 degrees



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Retrieved from "http://en.wikipedia.org/wiki/Triangle"
Categories: Geometric shapes | Polygons | Triangles

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2006-08-10 15:20:09 · answer #4 · answered by Neal J 4 · 1 2

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