Some people that answered my last question need to not answer this 1. If you do not know calculus don't try to answer the question. The answer is : -5 sin (5x) Jay H is getting the points. (Could that be Jay Haramy?). Next problem: S(-2Sin(Sin(2x))*Cos(2x))dx
2006-08-10 08:09:14 · 6 answers · asked by Dragonheart 2 in Science & Mathematics ➔ Mathematics
S(-2sin(sin(2x))cos(2x))dx
put sin 2x=t 2cos2xdx=dt
the integral=-2sint*dt/2
cost+c=cos(sin2x)+C
2006-08-10 08:23:22 · answer #1 · answered by raj 7 · 0⤊ 0⤋
Nope, not Jay Haramy. I look forward to the points, though. :-)
2006-08-10 09:03:13 · answer #2 · answered by Jay H 5 · 0⤊ 0⤋
I agree. cos(sin(2x))+c
Doug
2006-08-10 08:29:06 · answer #3 · answered by doug_donaghue 7 · 0⤊ 0⤋
i'm guessing that the Dx ability 'spinoff with know to x' (that's extra truthfully written d/dx) So e^(ln(cos(5x)) = cos(5x) and (d/dx)cos(5x) = -5sin(5x) yet notice, that's *in basic terms* valid over the area -?/10 < x < ?/10 (till you somewhat *want* the finished, complicated valued function over the finished z-airplane for -?/5 < x < ?/5. however the expression for that one is kinda ghastly) that's yet another occasion of ways hardship-free that's to screw the pooch in diagnosis. interior the unique function you need to take ln(cos(5x)) that's kewl as long as cos(5x)>0 by using fact ln(0) is undefined and ln of a damaging quantity is a complicated fee. Doug
2016-10-01 22:03:47 · answer #4 · answered by Anonymous · 0⤊ 0⤋
cos (sin 2x)
2006-08-10 08:47:37 · answer #5 · answered by Sakura X 2 · 0⤊ 0⤋
cos (sin 2x)
2006-08-10 08:20:18 · answer #6 · answered by Status: Paranoia 4 · 0⤊ 0⤋