linear inequalities
2006-08-10 07:34:18 · 10 answers · asked by lyn_zie2003 1 in Education & Reference ➔ Homework Help
always start by simplifing and trying to get the x's on the same side
5x - 7 -8x + 2 < 3(2x +5)
-3X -5 < 6x +15
-9X < 20
X > -20/9 (i think you flip the < > when you divide.. but you might want to double check that with your textbook)
2006-08-10 07:41:27 · answer #1 · answered by lexie 6 · 0⤊ 1⤋
3(2x+5)= 6x+15
5x-7-8x+2= -5-3x
Thus the new equation is
-5-3x=6x+15
-9x=20
x=-20/9
thus at x=-20/9 both equations have the same answer, so now you pick two numbers suxh as x=0 and x=-2 to find out which gives the correct statement above and say that x is either > or < than -20/9.
2006-08-10 07:43:22 · answer #2 · answered by Natasha B 4 · 0⤊ 0⤋
5x-7-8x+2<3(2x+5)
=>-3x-5<6x+15
=>-9x<20
=>x>-20/9 when you change the signs the sign
of inequalitychanges
2006-08-10 07:41:53 · answer #3 · answered by raj 7 · 0⤊ 0⤋
Expand the right hand side. Then take all the terms with 'x' to the left and all constants to the right. Add them just like you would any other normal addition. Then if the term in 'x' has a coefficient, divide both sides of the equation by that coefficient. Remeber to reverse the equality sign if the coefficient is negative.
Voilá, you have your answer.
Good luck!
2006-08-10 07:42:48 · answer #4 · answered by Stavi 2 · 0⤊ 0⤋
It's all about understanding the process.Solve each piece of the equation.
Do the left side and the right side separately. You must have already had enough algebra to solve a single variable equation.
After you've analyzed (reduced the complexity on) each side, you'll get to a result where "X=" something for each side.
Once you have that done, you can then compare the two two 'somethings' to determine if one must be less than the other.
2006-08-10 07:39:55 · answer #5 · answered by coragryph 7 · 0⤊ 1⤋
-3x-5<6x+15
-9x<20
x>-20
9
Does that help? Just remember that if you ahve to divide both sides by a negative number, the sign changes.
2006-08-10 07:41:34 · answer #6 · answered by Confusion With a K 7 · 0⤊ 0⤋
im not sure i think it might be 24<9x but im not sure if i did it wrong or not
2006-08-10 07:44:09 · answer #7 · answered by Emily 2 · 0⤊ 0⤋
http://www.hostsrv.com/webmab/app1/MSP/quickmath/02/pageGenerate?site=quickmath&s1=inequalities&s2=solve&s3=basic
go here it will do it for you and show you step by step
2006-08-10 07:44:50 · answer #8 · answered by Ashermunin 3 · 0⤊ 0⤋
http://www.purplemath.com/modules/ineqsolv.htm
2006-08-10 07:41:55 · answer #9 · answered by justmyjusrty 4 · 0⤊ 0⤋
Maybe you should look in your math book, and do your own homework....
2006-08-10 07:39:38 · answer #10 · answered by SillyQuestion 3 · 0⤊ 1⤋