both balls are the same size and shape
2006-08-10 03:35:10 · 18 answers · asked by tami 1 in Science & Mathematics ➔ Mathematics
If it happened on Earth than the lead one, but only because of wind resistance. If it were to happen on the moon then because there is no wind resistance they would both hit the ground at the same time.
2006-08-10 04:45:37 · answer #1 · answered by Mlsig 5 · 0⤊ 0⤋
It depends.
They are not the same weight. The heavier ball will accumulate more momentum compared to the rubber ball. So what?
If they are dropped in air, the air will resist their passage. It takes energy to move the air out of the way. The lead ball has more energy available to move the air out of the way. The rubber ball will be slowed more by the air.
In this case, the lead ball will reach the ground first.
The same would occur if they were dropped in water.
However, if they were dropped in a vacuum such as on the Moon, they would fall at the same rate, and land at the same time. But the lead ball would penetrate to a deeper depth than the rubber ball.
Consider what would happen if you dropped a ballon filled with air and a balloon filled with water out of the window. What would happen? (Same size and shape balloons) The weight relative to the air does matter. On the Moon, both would fall together, but the water ballon would make a splat, bursting the ballon. (Assuming enough velocity) The air filled ballon would simply bounce.
;-D Play ball!
2006-08-10 03:51:49 · answer #2 · answered by China Jon 6 · 1⤊ 0⤋
This does depend on whether we drop the balls in vacuum. If they are in vacuum then they will drop at the same rate and hit the ground at the same time.However, considering the fact that rubber is less dense than lead which means rubber has lesser mass per unit vol. as compared to lead, lead will hit the ground first (outside vacuum). This is because the rubber ball reaches terminal velocity much earlier than lead hence lead will hit the ground first.
2006-08-10 09:39:13 · answer #3 · answered by the_dreaded_curser 1 · 0⤊ 0⤋
The balls would hit the ground at the same time
2006-08-10 07:21:32 · answer #4 · answered by SAMUEL D 7 · 0⤊ 0⤋
Both would hit the ground at the same time.
2006-08-10 03:43:31 · answer #5 · answered by Seraphina // #1 born Aug 10 ^_^ 2 · 0⤊ 0⤋
Both would hit the ground at the same time.
2006-08-10 03:40:02 · answer #6 · answered by Anonymous · 1⤊ 0⤋
If you were to throw an elephant and an ant off a building simaltaneously, they would both hit the ground at the same.
But normally this is not possible because of air. Air causes bodies which are light and/or have a large surface area to slow down.
2006-08-10 04:02:22 · answer #7 · answered by jimmy_siddhartha 4 · 0⤊ 0⤋
They both hit the ground at the same time.
2006-08-10 03:39:54 · answer #8 · answered by booboo 7 · 1⤊ 0⤋
the lead ball will fall first under all circumstances. the previous guy is wrong the wind resistance will be same because they have same radius(because of stokes law) so the same opossing foece acts on both and since f=ma the upward accelaration is more on the rubber ball so the lead ball falls first
beleive me i am a science student
2006-08-10 03:50:12 · answer #9 · answered by keerthan 2 · 0⤊ 0⤋
In a vaccuum they would hit at the exact same time... however if you dropped them from high enough as to where wind resistance started effecting their motion, the lead would likely hit first.
2006-08-10 03:44:56 · answer #10 · answered by AresIV 4 · 0⤊ 0⤋