|6x + 25| + 14 < 6
2006-08-10 02:26:09 · 7 answers · asked by Rocstarr 2 in Science & Mathematics ➔ Mathematics
|6x + 25| >=0 for any x.
So |6x + 25| + 14 >= 14
So never is |6x + 25| + 14 < 6
There is no solution.
Th
2006-08-10 03:56:45 · answer #1 · answered by Thermo 6 · 0⤊ 0⤋
Absolute value inequalities are always so much fun. But ones like this are even more fun...
| 6x + 25 | + 14 < 6
| 6x + 25 | < -8
The answer is x does not exist.
By definition, for all n, | n | ≥ 0 (absolute value of n is greater than or equal to zero); so there is no value you could enter for x to make the expression | 6x + 25 | less than zero.
Hope this helps
2006-08-10 02:57:20 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Absolute value inequalities are always *so* much fun. But ones like this are even more fun...
| 6x + 25 | + 14 < 6
| 6x + 25 | < -8
The answer is x does not exist.
By definition, for all n, | n | ≥ 0 (absolute value of n is greater than or equal to zero); so there is no value you could enter for x to make the expression | 6x + 25 | less than zero.
2006-08-10 02:48:10 · answer #3 · answered by hogan.enterprises 5 · 0⤊ 0⤋
|6x + 25| + 14 < 6
|6x + 25| < -8
a modulus having a negative value is impossible so there is no solution
or if you meant
|6x + 25| + 14> 6
|6x + 25| > -8
since all moulus functions are greater than zero the soln is
x belongs to R
2006-08-10 02:36:21 · answer #4 · answered by keerthan 2 · 1⤊ 0⤋
|6x+25|+14 < 6
|6x+25| < 6-14
|6x+25| < -8
Because |6x+25| >= 0 for any value of x, there is no value of real number that satisfy the equation.
2006-08-10 02:43:36 · answer #5 · answered by r083r70v1ch 4 · 0⤊ 0⤋
Move 14 over and solve for both positive and negative values of the absolute figure
2006-08-10 02:31:43 · answer #6 · answered by zy 3 · 0⤊ 0⤋
vote democratic |absolutely|
2006-08-10 02:56:46 · answer #7 · answered by shazam 6 · 0⤊ 0⤋