English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

2006-08-10 02:19:22 · 2 answers · asked by goring 6 in Science & Mathematics Physics

2 answers

There is no force perpendicular to the radius vector from the sun to earth.

Therefore there is no acceleration of earth perpendicular to the radius.

The rate of change of angular speed which is the angular acceleration is zero.

But there is acceleration along the radius vector.

Due to the elliptical path described by the earth around the sun some may say that since the speed of earth is different at different positions there is angular acceleration.

As per Kepler’s law aerial velocity of a planet is constant.

The distance of earth to sun (radius) and the arc length covered are adjusted in such a way that the angular speed is constant, even though the linear speed varies.

If and only if the angular speed is constant, the aerial velocity will be constant.

If there were an angular acceleration then Kepler’s law will not be valid.

2006-08-10 05:09:47 · answer #1 · answered by Pearlsawme 7 · 1 0

Nice question. Are you referring to revolution around the sun or rotation about the axis? If it is the latter, I suggest that it will be a negative number (deceleration) resulting from tidal braking asserted on the earth by the moon's gravity.

2006-08-10 02:32:50 · answer #2 · answered by sparc77 7 · 1 0

fedest.com, questions and answers