2006-08-09 18:07:47 · 7 answers · asked by yeyet 1 in Education & Reference ➔ Homework Help
12C3/16C3=12*11*10/16*15*14=
Ans: 11/28
2006-08-09 18:17:20 · answer #1 · answered by deadlyfu 4 · 0⤊ 0⤋
38.88725. here's how i got the answer to make the first selection, the clinic has a 75% chance of picking a boy, or .75. in the second selection, the clinic has 11 boys left out of a remaining pool of 15 patients, which is .73. the last selection leaves the clinic with 10 boys out of 14 patients or .71. .75x.73x.71=.3888725 or 38.8725% chance of randomly selecting 3 boys at random from 16 students.
2006-08-10 01:21:37 · answer #2 · answered by Spellcaster97 2 · 0⤊ 0⤋
I'd have to agree with deadlyfu and spell caster.
Intuitively, we know that the likelihood of a specific event (i.e., selecting a boy) should decrease with each repetition. (Much like rolling a pair of sixes with dice many times in a row would be unusual). Also, assuming a boy is choosen each time, the total clinical population (16) as well as the total number of boys (12) will decrease by one with each selection. In mathematical terms, I believe this would be expressed like this:
12/16 * 11/15 * 10/14 = .3889 (38.89%)
2006-08-10 02:11:31 · answer #3 · answered by mindful1 3 · 0⤊ 0⤋
4:1
2006-08-10 01:15:53 · answer #4 · answered by progyas 2 · 0⤊ 0⤋
there is .75 or 75% probability that what u will select are boys...
add the number of boys and girls(16) then divide the number of boys to the total(12/16)....
2006-08-10 01:15:51 · answer #5 · answered by Anonymous · 0⤊ 0⤋
well, that makes it a 4 : 1 possiblity that all who are picked are boys.. so 75% they'll all be boys and 25% they're all girls//
2006-08-10 01:13:41 · answer #6 · answered by ☆Princess NonO☆ 4 · 0⤊ 0⤋
Crap, I forgot how to do that.
2006-08-10 01:11:39 · answer #7 · answered by gravytrain036 5 · 0⤊ 0⤋